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psf/black changes to next_greater_element.py (#1817)
* psf/black changes to next_greater_element.py * fixup! Format Python code with psf/black push Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
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@ -1,11 +1,14 @@
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arr = [-10, -5, 0, 5, 5.1, 11, 13, 21, 3, 4, -21, -10, -5, -1, 0]
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expect = [-5, 0, 5, 5.1, 11, 13, 21, -1, 4, -1, -10, -5, -1, 0, -1]
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def next_greatest_element_slow(arr):
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def next_greatest_element_slow(arr: list) -> list:
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"""
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Function to get Next Greatest Element (NGE) pair for all elements of list
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Maximum element present afterwards the current one which is also greater than current one
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>>> next_greatest_element_slow(arr)
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[-5, 0, 5, 5.1, 11, 13, 21, -1, 4, -1, -10, -5, -1, 0, -1]
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Get the Next Greatest Element (NGE) for all elements in a list.
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Maximum element present after the current one which is also greater than the
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current one.
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>>> next_greatest_element_slow(arr) == expect
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True
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"""
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result = []
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for i in range(0, len(arr), 1):
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@ -18,18 +21,18 @@ def next_greatest_element_slow(arr):
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return result
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def next_greatest_element_fast(arr):
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def next_greatest_element_fast(arr: list) -> list:
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"""
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Like next_greatest_element_slow() but changes the loops to use
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enumerate() instead of range(len()) for the outer loop and
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for in a slice of arr for the inner loop.
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>>> next_greatest_element_fast(arr)
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[-5, 0, 5, 5.1, 11, 13, 21, -1, 4, -1, -10, -5, -1, 0, -1]
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>>> next_greatest_element_fast(arr) == expect
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True
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"""
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result = []
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for i, outer in enumerate(arr):
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next = -1
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for inner in arr[i + 1:]:
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for inner in arr[i + 1 :]:
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if outer < inner:
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next = inner
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break
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@ -37,20 +40,21 @@ def next_greatest_element_fast(arr):
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return result
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def next_greatest_element(arr):
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def next_greatest_element(arr: list) -> list:
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"""
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Function to get Next Greatest Element (NGE) pair for all elements of list
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Maximum element present afterwards the current one which is also greater than current one
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Naive way to solve this is to take two loops and check for the next bigger number but that will make the
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time complexity as O(n^2). The better way to solve this would be to use a stack to keep track of maximum
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number givig a linear time complex solution.
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>>> next_greatest_element(arr)
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[-5, 0, 5, 5.1, 11, 13, 21, -1, 4, -1, -10, -5, -1, 0, -1]
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Get the Next Greatest Element (NGE) for all elements in a list.
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Maximum element present after the current one which is also greater than the
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current one.
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A naive way to solve this is to take two loops and check for the next bigger
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number but that will make the time complexity as O(n^2). The better way to solve
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this would be to use a stack to keep track of maximum number giving a linear time
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solution.
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>>> next_greatest_element(arr) == expect
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True
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"""
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stack = []
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result = [-1]*len(arr)
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stack = []
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result = [-1] * len(arr)
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for index in reversed(range(len(arr))):
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if len(stack):
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@ -63,7 +67,7 @@ def next_greatest_element(arr):
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result[index] = stack[-1]
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stack.append(arr[index])
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return result
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@ -76,11 +80,19 @@ if __name__ == "__main__":
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print(next_greatest_element_fast(arr))
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print(next_greatest_element(arr))
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setup = ("from __main__ import arr, next_greatest_element_slow, "
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"next_greatest_element_fast, next_greatest_element")
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print("next_greatest_element_slow():",
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timeit("next_greatest_element_slow(arr)", setup=setup))
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print("next_greatest_element_fast():",
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timeit("next_greatest_element_fast(arr)", setup=setup))
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print(" next_greatest_element():",
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timeit("next_greatest_element(arr)", setup=setup))
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setup = (
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"from __main__ import arr, next_greatest_element_slow, "
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"next_greatest_element_fast, next_greatest_element"
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)
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print(
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"next_greatest_element_slow():",
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timeit("next_greatest_element_slow(arr)", setup=setup),
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)
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print(
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"next_greatest_element_fast():",
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timeit("next_greatest_element_fast(arr)", setup=setup),
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)
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print(
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" next_greatest_element():",
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timeit("next_greatest_element(arr)", setup=setup),
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)
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@ -38,19 +38,21 @@ def allocation_num(number_of_bytes: int, partitions: int) -> List[str]:
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ValueError: partitions must be a positive number!
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"""
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if partitions <= 0:
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raise ValueError('partitions must be a positive number!')
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raise ValueError("partitions must be a positive number!")
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if partitions >= number_of_bytes:
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raise ValueError('partitions can not >= number_of_bytes!')
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raise ValueError("partitions can not >= number_of_bytes!")
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bytes_per_partition = number_of_bytes // partitions
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allocation_list = [f'0-{bytes_per_partition}']
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allocation_list = [f"0-{bytes_per_partition}"]
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for i in range(1, partitions - 1):
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length = f'{bytes_per_partition * i + 1}-{bytes_per_partition * (i + 1)}'
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length = f"{bytes_per_partition * i + 1}-{bytes_per_partition * (i + 1)}"
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allocation_list.append(length)
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allocation_list.append(f'{(bytes_per_partition * (partitions - 1)) + 1}-'
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f'{number_of_bytes}')
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allocation_list.append(
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f"{(bytes_per_partition * (partitions - 1)) + 1}-" f"{number_of_bytes}"
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)
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return allocation_list
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if __name__ == '__main__':
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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