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Added the algorithm to compute Reynolds number in the physics section (#9913)
* added the algorithm to compute Reynolds number * fixed file name issue * Apply suggestions from code review --------- Co-authored-by: Tianyi Zheng <tianyizheng02@gmail.com>
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physics/reynolds_number.py
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physics/reynolds_number.py
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"""
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Title : computing the Reynolds number to find
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out the type of flow (laminar or turbulent)
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Reynolds number is a dimensionless quantity that is used to determine
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the type of flow pattern as laminar or turbulent while flowing through a
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pipe. Reynolds number is defined by the ratio of inertial forces to that of
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viscous forces.
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R = Inertial Forces / Viscous Forces
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R = (ρ * V * D)/μ
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where :
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ρ = Density of fluid (in Kg/m^3)
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D = Diameter of pipe through which fluid flows (in m)
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V = Velocity of flow of the fluid (in m/s)
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μ = Viscosity of the fluid (in Ns/m^2)
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If the Reynolds number calculated is high (greater than 2000), then the
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flow through the pipe is said to be turbulent. If Reynolds number is low
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(less than 2000), the flow is said to be laminar. Numerically, these are
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acceptable values, although in general the laminar and turbulent flows
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are classified according to a range. Laminar flow falls below Reynolds
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number of 1100 and turbulent falls in a range greater than 2200.
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Laminar flow is the type of flow in which the fluid travels smoothly in
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regular paths. Conversely, turbulent flow isn't smooth and follows an
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irregular path with lots of mixing.
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Reference : https://byjus.com/physics/reynolds-number/
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"""
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def reynolds_number(
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density: float, velocity: float, diameter: float, viscosity: float
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) -> float:
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"""
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>>> reynolds_number(900, 2.5, 0.05, 0.4)
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281.25
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>>> reynolds_number(450, 3.86, 0.078, 0.23)
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589.0695652173912
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>>> reynolds_number(234, -4.5, 0.3, 0.44)
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717.9545454545454
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>>> reynolds_number(-90, 2, 0.045, 1)
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Traceback (most recent call last):
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...
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ValueError: please ensure that density, diameter and viscosity are positive
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>>> reynolds_number(0, 2, -0.4, -2)
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Traceback (most recent call last):
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...
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ValueError: please ensure that density, diameter and viscosity are positive
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"""
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if density <= 0 or diameter <= 0 or viscosity <= 0:
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raise ValueError(
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"please ensure that density, diameter and viscosity are positive"
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)
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return (density * abs(velocity) * diameter) / viscosity
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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