Merge 621a09f074 into 9a572dec2b

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matrix/diagonal_traversal.py

@@ -0,0 +1,67 @@
+from typing import list
+
+
+def find_diagonal_order(mat: list[list[int]]) -> list[int]:
+    """
+    Returns the elements of the matrix in diagonal order.
+
+    :param mat: A 2D list representing the matrix.
+    :return: A list of elements in diagonal order.
+    :raises ValueError: If the matrix is empty or rows have different lengths.
+
+    >>> find_diagonal_order([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
+    [1, 2, 4, 7, 5, 3, 6, 8, 9]
+
+    Example:
+    matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
+    Algorithm:
+        Step 1. Initialize variables to track the current row and column.
+        Step 2. Iterate through the elements of the matrix in a
+                manner that alternates between moving diagonally up
+                and down.
+    """
+    if not mat or not mat[0]:
+        return []
+
+    m, n = len(mat), len(mat[0])
+
+    # Check for uniformity of row lengths
+    for row in mat:
+        if len(row) != n:
+            raise ValueError("All rows must have the same number of columns.")
+
+    result = []
+    row, col = 0, 0
+
+    for _ in range(m * n):
+        result.append(mat[row][col])
+
+        # Determine the direction of traversal
+        if (row + col) % 2 == 0:  # moving up
+            if col == n - 1:  # hit the right boundary
+                row += 1
+            elif row == 0:  # hit the top boundary
+                col += 1
+            else:  # move up diagonally
+                row -= 1
+                col += 1
+        elif row == m - 1:  # hit the bottom boundary
+            col += 1
+        elif col == 0:  # hit the left boundary
+            row += 1
+        elif col > 0 and row < m - 1:  # move down diagonally
+            row += 1
+            col -= 1
+
+    return result
+
+
+# Driver code
+if __name__ == "__main__":
+    import doctest
+
+    doctest.testmod()
+
+    # Example usage
+    matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
+    print(find_diagonal_order(matrix))