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72
sorts/binarysearch_on_sorted_2d_array.py
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72
sorts/binarysearch_on_sorted_2d_array.py
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#!/usr/bin/env python3
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def binary_search_2d(matrix: list[list[int]], target: int) -> tuple[int, int]:
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"""
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Searches for a target value in a 2D sorted array.
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The matrix is sorted such that each row is in ascending order, and the
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first element of each row is greater than the last element of the previous row.
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Args:
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matrix: A 2D list of integers sorted in ascending order.
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target: The integer value to search for.
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Returns:
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A tuple (row_index, col_index) if found, otherwise (-1, -1).
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Raises:
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ValueError: If matrix is empty or not rectangular.
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>>> binary_search_2d([[1, 3, 5], [7, 9, 11], [12, 13, 15]], 9)
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(1, 1)
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>>> binary_search_2d([[1, 3, 5], [7, 9, 11], [12, 13, 15]], 4)
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(-1, -1)
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>>> binary_search_2d([], 1) # doctest: +ELLIPSIS
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Traceback (most recent call last):
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...
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ValueError: matrix must not be empty
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>>> binary_search_2d([[1, 2], [3, 4, 5]], 3) # doctest: +ELLIPSIS
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Traceback (most recent call last):
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...
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ValueError: matrix must be rectangular
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"""
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if not matrix or not matrix[0]:
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raise ValueError("matrix must not be empty")
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rows = len(matrix)
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cols = len(matrix[0])
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for row in matrix:
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if len(row) != cols:
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raise ValueError("matrix must be rectangular")
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left, right = 0, rows * cols - 1
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while left <= right:
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mid = left + (right - left) // 2
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mid_value = matrix[mid // cols][mid % cols]
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if mid_value == target:
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return mid // cols, mid % cols
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elif mid_value < target:
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left = mid + 1
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else:
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right = mid - 1
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return -1, -1
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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# Example usage
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matrix = [[1, 3, 5], [7, 9, 11], [12, 13, 15]]
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target = 9
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result = binary_search_2d(matrix, target)
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if result == (-1, -1):
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print(f"{target} was not found in the matrix.")
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else:
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print(f"{target} was found at position {result} in the matrix.")
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