""" Project Euler Problem 79: https://projecteuler.net/problem=79 Passcode derivation A common security method used for online banking is to ask the user for three random characters from a passcode. For example, if the passcode was 531278, they may ask for the 2nd, 3rd, and 5th characters; the expected reply would be: 317. The text file, keylog.txt, contains fifty successful login attempts. Given that the three characters are always asked for in order, analyse the file so as to determine the shortest possible secret passcode of unknown length. """ import itertools from pathlib import Path def find_secret_passcode(logins: list[str]) -> int: """ Returns the shortest possible secret passcode of unknown length. >>> find_secret_passcode(["135", "259", "235", "189", "690", "168", "120", ... "136", "289", "589", "160", "165", "580", "369", "250", "280"]) 12365890 >>> find_secret_passcode(["426", "281", "061", "819" "268", "406", "420", ... "428", "209", "689", "019", "421", "469", "261", "681", "201"]) 4206819 """ # Split each login by character e.g. '319' -> ('3', '1', '9') split_logins = [tuple(login) for login in logins] unique_chars = {char for login in split_logins for char in login} for permutation in itertools.permutations(unique_chars): satisfied = True for login in logins: if not ( permutation.index(login[0]) < permutation.index(login[1]) < permutation.index(login[2]) ): satisfied = False break if satisfied: return int("".join(permutation)) raise Exception("Unable to find the secret passcode") def solution(input_file: str = "keylog.txt") -> int: """ Returns the shortest possible secret passcode of unknown length for successful login attempts given by `input_file` text file. >>> solution("keylog_test.txt") 6312980 """ logins = Path(__file__).parent.joinpath(input_file).read_text().splitlines() return find_secret_passcode(logins) if __name__ == "__main__": print(f"{solution() = }")