# solved #001
"""
Project Euler Problem 1: https://projecteuler.net/problem=1

Multiples of 3 or 5

"""

def solution(n: int = 1000) -> int:
    """
    For number i in 1 to 1000 we take modulus of 3 and 5 with each number and when any of their value is zero we add that number to sum_count varialbe.

    """
    n = 1000
    sum_count = 0
    for i in range(1,n+1):
        if i%3==0 or i%5==0:
            sum_count += i

    return sum_count


if __name__ == "__main__":
    print(f"{solution() = }")