""" This is pure Python implementation of interpolation search algorithm """ def interpolation_search(sorted_collection: list[int], item: int) -> int | None: """ Searches for an item in a sorted collection by interpolation search algorithm. Args: sorted_collection: sorted list of integers item: item value to search Returns: int: The index of the found item, or None if the item is not found. Examples: >>> interpolation_search([1, 2, 3, 4, 5], 2) 1 >>> interpolation_search([1, 2, 3, 4, 5], 4) 3 >>> interpolation_search([1, 2, 3, 4, 5], 6) is None True >>> interpolation_search([], 1) is None True >>> interpolation_search([100], 100) 0 >>> interpolation_search([1, 2, 3, 4, 5], 0) is None True >>> interpolation_search([1, 2, 3, 4, 5], 7) is None True >>> interpolation_search([1, 2, 3, 4, 5], 2) 1 >>> interpolation_search([1, 2, 3, 4, 5], 0) is None True >>> interpolation_search([1, 2, 3, 4, 5], 7) is None True >>> interpolation_search([1, 2, 3, 4, 5], 2) 1 >>> interpolation_search([5, 5, 5, 5, 5], 3) is None True """ left = 0 right = len(sorted_collection) - 1 while left <= right: # avoid divided by 0 during interpolation if sorted_collection[left] == sorted_collection[right]: if sorted_collection[left] == item: return left return None point = left + ((item - sorted_collection[left]) * (right - left)) // ( sorted_collection[right] - sorted_collection[left] ) # out of range check if point < 0 or point >= len(sorted_collection): return None current_item = sorted_collection[point] if current_item == item: return point if point < left: right = left left = point elif point > right: left = right right = point elif item < current_item: right = point - 1 else: left = point + 1 return None def interpolation_search_by_recursion( sorted_collection: list[int], item: int, left: int = 0, right: int | None = None ) -> int | None: """Pure implementation of interpolation search algorithm in Python by recursion Be careful collection must be ascending sorted, otherwise result will be unpredictable First recursion should be started with left=0 and right=(len(sorted_collection)-1) Args: sorted_collection: some sorted collection with comparable items item: item value to search left: left index in collection right: right index in collection Returns: index of item in collection or None if item is not present Examples: >>> interpolation_search_by_recursion([0, 5, 7, 10, 15], 0) 0 >>> interpolation_search_by_recursion([0, 5, 7, 10, 15], 15) 4 >>> interpolation_search_by_recursion([0, 5, 7, 10, 15], 5) 1 >>> interpolation_search_by_recursion([0, 5, 7, 10, 15], 100) is None True >>> interpolation_search_by_recursion([5, 5, 5, 5, 5], 3) is None True """ if right is None: right = len(sorted_collection) - 1 # avoid divided by 0 during interpolation if sorted_collection[left] == sorted_collection[right]: if sorted_collection[left] == item: return left return None point = left + ((item - sorted_collection[left]) * (right - left)) // ( sorted_collection[right] - sorted_collection[left] ) # out of range check if point < 0 or point >= len(sorted_collection): return None if sorted_collection[point] == item: return point if point < left: return interpolation_search_by_recursion(sorted_collection, item, point, left) if point > right: return interpolation_search_by_recursion(sorted_collection, item, right, left) if sorted_collection[point] > item: return interpolation_search_by_recursion( sorted_collection, item, left, point - 1 ) return interpolation_search_by_recursion(sorted_collection, item, point + 1, right) if __name__ == "__main__": import doctest doctest.testmod()