""" Python implementation of the MSD radix sort algorithm. It used the binary representation of the integers to sort them. https://en.wikipedia.org/wiki/Radix_sort """ from typing import List def msd_radix_sort(list_of_ints: List[int]) -> List[int]: """ Implementation of the MSD radix sort algorithm. Only works with positive integers :param list_of_ints: A list of integers :return: Returns the sorted list >>> msd_radix_sort([40, 12, 1, 100, 4]) [1, 4, 12, 40, 100] >>> msd_radix_sort([]) [] >>> msd_radix_sort([123, 345, 123, 80]) [80, 123, 123, 345] >>> msd_radix_sort([1209, 834598, 1, 540402, 45]) [1, 45, 1209, 540402, 834598] >>> msd_radix_sort([-1, 34, 45]) Traceback (most recent call last): ... ValueError: All numbers must be positive """ if not list_of_ints: return [] if min(list_of_ints) < 0: raise ValueError("All numbers must be positive") most_bits = max(len(bin(x)[2:]) for x in list_of_ints) return _msd_radix_sort(list_of_ints, most_bits) def _msd_radix_sort(list_of_ints: List[int], bit_position: int) -> List[int]: """ Sort the given list based on the bit at bit_position. Numbers with a 0 at that position will be at the start of the list, numbers with a 1 at the end. :param list_of_ints: A list of integers :param bit_position: the position of the bit that gets compared :return: Returns a partially sorted list >>> _msd_radix_sort([45, 2, 32], 1) [2, 32, 45] >>> _msd_radix_sort([10, 4, 12], 2) [4, 12, 10] """ if bit_position == 0 or len(list_of_ints) in [0, 1]: return list_of_ints zeros = list() ones = list() # Split numbers based on bit at bit_position from the right for number in list_of_ints: if (number >> (bit_position - 1)) & 1: # number has a one at bit bit_position ones.append(number) else: # number has a zero at bit bit_position zeros.append(number) # recursively split both lists further zeros = _msd_radix_sort(zeros, bit_position - 1) ones = _msd_radix_sort(ones, bit_position - 1) # recombine lists res = zeros res.extend(ones) return res def msd_radix_sort_inplace(list_of_ints: List[int]): """ Inplace implementation of the MSD radix sort algorithm. Sorts based on the binary representation of the integers. >>> lst = [1, 345, 23, 89, 0, 3] >>> msd_radix_sort_inplace(lst) >>> lst == sorted(lst) True >>> lst = [1, 43, 0, 0, 0, 24, 3, 3] >>> msd_radix_sort_inplace(lst) >>> lst == sorted(lst) True >>> lst = [] >>> msd_radix_sort_inplace(lst) >>> lst == [] True >>> lst = [-1, 34, 23, 4, -42] >>> msd_radix_sort_inplace(lst) Traceback (most recent call last): ... ValueError: All numbers must be positive """ length = len(list_of_ints) if not list_of_ints or length == 1: return if min(list_of_ints) < 0: raise ValueError("All numbers must be positive") most_bits = max(len(bin(x)[2:]) for x in list_of_ints) _msd_radix_sort_inplace(list_of_ints, most_bits, 0, length) def _msd_radix_sort_inplace( list_of_ints: List[int], bit_position: int, begin_index: int, end_index: int ): """ Sort the given list based on the bit at bit_position. Numbers with a 0 at that position will be at the start of the list, numbers with a 1 at the end. >>> lst = [45, 2, 32, 24, 534, 2932] >>> _msd_radix_sort_inplace(lst, 1, 0, 3) >>> lst == [32, 2, 45, 24, 534, 2932] True >>> lst = [0, 2, 1, 3, 12, 10, 4, 90, 54, 2323, 756] >>> _msd_radix_sort_inplace(lst, 2, 4, 7) >>> lst == [0, 2, 1, 3, 12, 4, 10, 90, 54, 2323, 756] True """ if bit_position == 0 or end_index - begin_index <= 1: return bit_position -= 1 i = begin_index j = end_index - 1 while i <= j: changed = False if not ((list_of_ints[i] >> bit_position) & 1): # found zero at the beginning i += 1 changed = True if (list_of_ints[j] >> bit_position) & 1: # found one at the end j -= 1 changed = True if changed: continue list_of_ints[i], list_of_ints[j] = list_of_ints[j], list_of_ints[i] j -= 1 if not j == i: i += 1 _msd_radix_sort_inplace(list_of_ints, bit_position, begin_index, i) _msd_radix_sort_inplace(list_of_ints, bit_position, i, end_index) if __name__ == "__main__": import doctest doctest.testmod()