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de3271ec80
* Refactoring the syntax using list comprehension * Update detecting_english_programmatically.py * Update detecting_english_programmatically.py Co-authored-by: Christian Clauss <cclauss@me.com>
51 lines
1.4 KiB
Python
51 lines
1.4 KiB
Python
import os
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from string import ascii_letters
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LETTERS_AND_SPACE = ascii_letters + " \t\n"
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def load_dictionary() -> dict[str, None]:
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path = os.path.split(os.path.realpath(__file__))
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english_words: dict[str, None] = {}
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with open(path[0] + "/dictionary.txt") as dictionary_file:
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for word in dictionary_file.read().split("\n"):
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english_words[word] = None
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return english_words
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ENGLISH_WORDS = load_dictionary()
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def get_english_count(message: str) -> float:
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message = message.upper()
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message = remove_non_letters(message)
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possible_words = message.split()
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matches = len([word for word in possible_words if word in ENGLISH_WORDS])
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return float(matches) / len(possible_words)
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def remove_non_letters(message: str) -> str:
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return "".join(symbol for symbol in message if symbol in LETTERS_AND_SPACE)
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def is_english(
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message: str, word_percentage: int = 20, letter_percentage: int = 85
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) -> bool:
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"""
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>>> is_english('Hello World')
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True
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>>> is_english('llold HorWd')
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False
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"""
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words_match = get_english_count(message) * 100 >= word_percentage
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num_letters = len(remove_non_letters(message))
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message_letters_percentage = (float(num_letters) / len(message)) * 100
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letters_match = message_letters_percentage >= letter_percentage
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return words_match and letters_match
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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