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927e14e7f2
* mv str statement into docstr * rename var to avoid redefining builtin * clean up module docstr
61 lines
1.2 KiB
Python
61 lines
1.2 KiB
Python
"""
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Problem Statement:
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If we list all the natural numbers below 10 that are multiples of 3 or 5,
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we get 3, 5, 6 and 9. The sum of these multiples is 23.
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Find the sum of all the multiples of 3 or 5 below N.
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"""
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def solution(n: int = 1000) -> int:
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"""
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This solution is based on the pattern that the successive numbers in the
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series follow: 0+3,+2,+1,+3,+1,+2,+3.
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Returns the sum of all the multiples of 3 or 5 below n.
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>>> solution(3)
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0
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>>> solution(4)
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3
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>>> solution(10)
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23
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>>> solution(600)
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83700
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"""
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total = 0
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num = 0
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while 1:
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num += 3
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if num >= n:
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break
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total += num
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num += 2
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if num >= n:
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break
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total += num
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num += 1
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if num >= n:
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break
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total += num
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num += 3
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if num >= n:
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break
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total += num
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num += 1
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if num >= n:
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break
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total += num
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num += 2
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if num >= n:
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break
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total += num
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num += 3
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if num >= n:
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break
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total += num
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return total
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if __name__ == "__main__":
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print(solution(int(input().strip())))
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