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77 lines
2.1 KiB
Python
77 lines
2.1 KiB
Python
"""
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Project Euler Problem 092: https://projecteuler.net/problem=92
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Square digit chains
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A number chain is created by continuously adding the square of the digits in
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a number to form a new number until it has been seen before.
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For example,
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44 → 32 → 13 → 10 → 1 → 1
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85 → 89 → 145 → 42 → 20 → 4 → 16 → 37 → 58 → 89
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Therefore any chain that arrives at 1 or 89 will become stuck in an endless loop.
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What is most amazing is that EVERY starting number will eventually arrive at 1 or 89.
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How many starting numbers below ten million will arrive at 89?
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"""
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def next_number(number: int) -> int:
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"""
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Returns the next number of the chain by adding the square of each digit
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to form a neww number.
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For example if number = 12, next_number() will return 1^2 + 2^2 = 5.
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Therefore, 5 is the next number of the chain.
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>>> next_number(44)
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32
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>>> next_number(10)
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1
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>>> next_number(32)
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13
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"""
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sum_of_digits_squared = 0
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while number:
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sum_of_digits_squared += (number % 10) ** 2
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number //= 10
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return sum_of_digits_squared
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def chain(number: int) -> bool:
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"""
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The function generates the chain of numbers until the next number is 1 or 89.
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For example, if starting number is 44, then the function generates the
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following chain of numbers:
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44 → 32 → 13 → 10 → 1 → 1.
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Once the next number generated is 1 or 89, the function returns whether
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or not the the next number generated by next_number() is 1.
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>>> chain(10)
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True
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>>> chain(58)
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False
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>>> chain(1)
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True
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"""
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while number != 1 and number != 89:
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number = next_number(number)
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return number == 1
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def solution(number: int = 10000000) -> int:
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"""
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The function returns the number of integers that end up being 89 in each chain.
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The function accepts a range number and the function checks all the values
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under value number.
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>>> solution(100)
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80
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>>> solution(10000000)
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8581146
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"""
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return sum(1 for i in range(1, number) if not chain(i))
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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print(f"{solution() = }")
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