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* ci(pre-commit): Add ``flake8-builtins`` additional dependency to ``pre-commit`` (#7104) * refactor: Fix ``flake8-builtins`` (#7104) * fix(lru_cache): Fix naming conventions in docstrings (#7104) * ci(pre-commit): Order additional dependencies alphabetically (#7104) * fix(lfu_cache): Correct function name in docstring (#7104) * Update strings/snake_case_to_camel_pascal_case.py Co-authored-by: Christian Clauss <cclauss@me.com> * Update data_structures/stacks/next_greater_element.py Co-authored-by: Christian Clauss <cclauss@me.com> * Update digital_image_processing/index_calculation.py Co-authored-by: Christian Clauss <cclauss@me.com> * Update graphs/prim.py Co-authored-by: Christian Clauss <cclauss@me.com> * Update hashes/djb2.py Co-authored-by: Christian Clauss <cclauss@me.com> * refactor: Rename `_builtin` to `builtin_` ( #7104) * fix: Rename all instances (#7104) * refactor: Update variable names (#7104) * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * ci: Create ``tox.ini`` and ignore ``A003`` (#7123) * revert: Remove function name changes (#7104) * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Rename tox.ini to .flake8 * Update data_structures/heap/heap.py Co-authored-by: Dhruv Manilawala <dhruvmanila@gmail.com> * refactor: Rename `next_` to `next_item` (#7104) * ci(pre-commit): Add `flake8` plugin `flake8-bugbear` (#7127) * refactor: Follow `flake8-bugbear` plugin (#7127) * fix: Correct `knapsack` code (#7127) * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci Co-authored-by: Christian Clauss <cclauss@me.com> Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Dhruv Manilawala <dhruvmanila@gmail.com>
61 lines
1.5 KiB
Python
61 lines
1.5 KiB
Python
"""
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Euler Problem 26
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https://projecteuler.net/problem=26
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Problem Statement:
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A unit fraction contains 1 in the numerator. The decimal representation of the
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unit fractions with denominators 2 to 10 are given:
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1/2 = 0.5
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1/3 = 0.(3)
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1/4 = 0.25
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1/5 = 0.2
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1/6 = 0.1(6)
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1/7 = 0.(142857)
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1/8 = 0.125
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1/9 = 0.(1)
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1/10 = 0.1
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Where 0.1(6) means 0.166666..., and has a 1-digit recurring cycle. It can be
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seen that 1/7 has a 6-digit recurring cycle.
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Find the value of d < 1000 for which 1/d contains the longest recurring cycle
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in its decimal fraction part.
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"""
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def solution(numerator: int = 1, digit: int = 1000) -> int:
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"""
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Considering any range can be provided,
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because as per the problem, the digit d < 1000
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>>> solution(1, 10)
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7
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>>> solution(10, 100)
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97
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>>> solution(10, 1000)
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983
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"""
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the_digit = 1
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longest_list_length = 0
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for divide_by_number in range(numerator, digit + 1):
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has_been_divided: list[int] = []
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now_divide = numerator
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for _ in range(1, digit + 1):
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if now_divide in has_been_divided:
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if longest_list_length < len(has_been_divided):
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longest_list_length = len(has_been_divided)
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the_digit = divide_by_number
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else:
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has_been_divided.append(now_divide)
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now_divide = now_divide * 10 % divide_by_number
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return the_digit
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# Tests
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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