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* feat: Add pronic number implementation * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com>
55 lines
1.3 KiB
Python
55 lines
1.3 KiB
Python
"""
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== Pronic Number ==
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A number n is said to be a Proic number if
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there exists an integer m such that n = m * (m + 1)
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Examples of Proic Numbers: 0, 2, 6, 12, 20, 30, 42, 56, 72, 90, 110 ...
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https://en.wikipedia.org/wiki/Pronic_number
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"""
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# Author : Akshay Dubey (https://github.com/itsAkshayDubey)
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def is_pronic(number: int) -> bool:
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"""
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# doctest: +NORMALIZE_WHITESPACE
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This functions takes an integer number as input.
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returns True if the number is pronic.
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>>> is_pronic(-1)
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False
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>>> is_pronic(0)
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True
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>>> is_pronic(2)
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True
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>>> is_pronic(5)
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False
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>>> is_pronic(6)
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True
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>>> is_pronic(8)
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False
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>>> is_pronic(30)
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True
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>>> is_pronic(32)
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False
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>>> is_pronic(2147441940)
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True
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>>> is_pronic(9223372033963249500)
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True
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>>> is_pronic(6.0)
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Traceback (most recent call last):
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...
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TypeError: Input value of [number=6.0] must be an integer
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"""
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if not isinstance(number, int):
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raise TypeError(f"Input value of [number={number}] must be an integer")
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if number < 0 or number % 2 == 1:
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return False
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number_sqrt = int(number**0.5)
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return number == number_sqrt * (number_sqrt + 1)
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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