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46af42d47a
* Removed unused variable m. * Doctests are modified to match functions. * Added condition for negative values. * Fixed white-space around operator. * Fixed W293 blank line contains white-space error. * Update dynamic_programming/coin_change.py Co-authored-by: Tapajyoti Bose <44058757+ruppysuppy@users.noreply.github.com> * Fixed error in code. * Fixed whited spacing. * Fixed PEP8 error. * Added more test cases for coin change problem. * Removed extra test for negetive value. Co-authored-by: Tapajyoti Bose <44058757+ruppysuppy@users.noreply.github.com>
47 lines
1.1 KiB
Python
47 lines
1.1 KiB
Python
"""
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You have m types of coins available in infinite quantities
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where the value of each coins is given in the array S=[S0,... Sm-1]
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Can you determine number of ways of making change for n units using
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the given types of coins?
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https://www.hackerrank.com/challenges/coin-change/problem
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"""
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def dp_count(S, n):
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"""
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>>> dp_count([1, 2, 3], 4)
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4
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>>> dp_count([1, 2, 3], 7)
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8
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>>> dp_count([2, 5, 3, 6], 10)
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5
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>>> dp_count([10], 99)
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0
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>>> dp_count([4, 5, 6], 0)
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1
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>>> dp_count([1, 2, 3], -5)
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0
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"""
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if n < 0:
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return 0
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# table[i] represents the number of ways to get to amount i
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table = [0] * (n + 1)
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# There is exactly 1 way to get to zero(You pick no coins).
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table[0] = 1
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# Pick all coins one by one and update table[] values
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# after the index greater than or equal to the value of the
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# picked coin
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for coin_val in S:
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for j in range(coin_val, n + 1):
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table[j] += table[j - coin_val]
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return table[n]
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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