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146800307c
* Add doctests to interpolation_search.py * update docs * update tests * update tests 2 * clean code
138 lines
4.2 KiB
Python
138 lines
4.2 KiB
Python
"""
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This is pure Python implementation of interpolation search algorithm
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"""
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def interpolation_search(sorted_collection: list[int], item: int) -> int | None:
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"""
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Searches for an item in a sorted collection by interpolation search algorithm.
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Args:
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sorted_collection: sorted list of integers
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item: item value to search
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Returns:
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int: The index of the found item, or None if the item is not found.
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Examples:
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>>> interpolation_search([1, 2, 3, 4, 5], 2)
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1
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>>> interpolation_search([1, 2, 3, 4, 5], 4)
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3
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>>> interpolation_search([1, 2, 3, 4, 5], 6) is None
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True
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>>> interpolation_search([], 1) is None
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True
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>>> interpolation_search([100], 100)
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0
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>>> interpolation_search([1, 2, 3, 4, 5], 0) is None
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True
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>>> interpolation_search([1, 2, 3, 4, 5], 7) is None
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True
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>>> interpolation_search([1, 2, 3, 4, 5], 2)
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1
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>>> interpolation_search([1, 2, 3, 4, 5], 0) is None
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True
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>>> interpolation_search([1, 2, 3, 4, 5], 7) is None
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True
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>>> interpolation_search([1, 2, 3, 4, 5], 2)
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1
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>>> interpolation_search([5, 5, 5, 5, 5], 3) is None
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True
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"""
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left = 0
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right = len(sorted_collection) - 1
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while left <= right:
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# avoid divided by 0 during interpolation
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if sorted_collection[left] == sorted_collection[right]:
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if sorted_collection[left] == item:
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return left
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return None
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point = left + ((item - sorted_collection[left]) * (right - left)) // (
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sorted_collection[right] - sorted_collection[left]
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)
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# out of range check
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if point < 0 or point >= len(sorted_collection):
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return None
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current_item = sorted_collection[point]
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if current_item == item:
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return point
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if point < left:
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right = left
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left = point
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elif point > right:
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left = right
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right = point
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elif item < current_item:
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right = point - 1
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else:
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left = point + 1
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return None
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def interpolation_search_by_recursion(
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sorted_collection: list[int], item: int, left: int = 0, right: int | None = None
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) -> int | None:
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"""Pure implementation of interpolation search algorithm in Python by recursion
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Be careful collection must be ascending sorted, otherwise result will be
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unpredictable
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First recursion should be started with left=0 and right=(len(sorted_collection)-1)
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Args:
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sorted_collection: some sorted collection with comparable items
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item: item value to search
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left: left index in collection
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right: right index in collection
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Returns:
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index of item in collection or None if item is not present
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Examples:
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>>> interpolation_search_by_recursion([0, 5, 7, 10, 15], 0)
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0
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>>> interpolation_search_by_recursion([0, 5, 7, 10, 15], 15)
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4
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>>> interpolation_search_by_recursion([0, 5, 7, 10, 15], 5)
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1
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>>> interpolation_search_by_recursion([0, 5, 7, 10, 15], 100) is None
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True
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>>> interpolation_search_by_recursion([5, 5, 5, 5, 5], 3) is None
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True
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"""
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if right is None:
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right = len(sorted_collection) - 1
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# avoid divided by 0 during interpolation
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if sorted_collection[left] == sorted_collection[right]:
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if sorted_collection[left] == item:
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return left
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return None
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point = left + ((item - sorted_collection[left]) * (right - left)) // (
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sorted_collection[right] - sorted_collection[left]
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)
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# out of range check
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if point < 0 or point >= len(sorted_collection):
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return None
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if sorted_collection[point] == item:
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return point
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if point < left:
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return interpolation_search_by_recursion(sorted_collection, item, point, left)
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if point > right:
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return interpolation_search_by_recursion(sorted_collection, item, right, left)
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if sorted_collection[point] > item:
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return interpolation_search_by_recursion(
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sorted_collection, item, left, point - 1
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)
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return interpolation_search_by_recursion(sorted_collection, item, point + 1, right)
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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