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31 lines
771 B
Python
31 lines
771 B
Python
def single_number(nums: list[int]) -> int:
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"""
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Find the single number in an array where every other number appears twice.
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Args:
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nums: List of integers where every integer appears twice except for one.
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Returns:
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The single integer that appears once.
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Example:
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>>> single_number([4, 1, 2, 1, 2])
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4
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>>> single_number([2, 2, 1])
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1
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>>> single_number([1])
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1
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"""
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result = 0
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for num in nums:
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result ^= num # Applying XOR operation
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return result
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if __name__ == "__main__":
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# Test cases
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print(single_number([4, 1, 2, 1, 2])) # Output: 4
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print(single_number([2, 2, 1])) # Output: 1
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print(single_number([1])) # Output: 1
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print(single_number([5, 3, 5, 7, 3])) # Output: 7
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