mirror of
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bcfca67faa
* [mypy] fix type annotations for problem003/sol1 and problem003/sol3 * [mypy] fix type annotations for project euler problem007/sol2 * [mypy] fix type annotations for project euler problem008/sol2 * [mypy] fix type annotations for project euler problem009/sol1 * [mypy] fix type annotations for project euler problem014/sol1 * [mypy] fix type annotations for project euler problem 025/sol2 * [mypy] fix type annotations for project euler problem026/sol1.py * [mypy] fix type annotations for project euler problem037/sol1 * [mypy] fix type annotations for project euler problem044/sol1 * [mypy] fix type annotations for project euler problem046/sol1 * [mypy] fix type annotations for project euler problem051/sol1 * [mypy] fix type annotations for project euler problem074/sol2 * [mypy] fix type annotations for project euler problem080/sol1 * [mypy] fix type annotations for project euler problem099/sol1 * [mypy] fix type annotations for project euler problem101/sol1 * [mypy] fix type annotations for project euler problem188/sol1 * [mypy] fix type annotations for project euler problem191/sol1 * [mypy] fix type annotations for project euler problem207/sol1 * [mypy] fix type annotations for project euler problem551/sol1
37 lines
1.0 KiB
Python
37 lines
1.0 KiB
Python
"""
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Problem:
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Comparing two numbers written in index form like 2'11 and 3'7 is not difficult, as any
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calculator would confirm that 2^11 = 2048 < 3^7 = 2187.
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However, confirming that 632382^518061 > 519432^525806 would be much more difficult, as
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both numbers contain over three million digits.
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Using base_exp.txt, a 22K text file containing one thousand lines with a base/exponent
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pair on each line, determine which line number has the greatest numerical value.
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NOTE: The first two lines in the file represent the numbers in the example given above.
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"""
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import os
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from math import log10
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def solution(data_file: str = "base_exp.txt") -> int:
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"""
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>>> solution()
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709
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"""
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largest: float = 0
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result = 0
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for i, line in enumerate(open(os.path.join(os.path.dirname(__file__), data_file))):
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a, x = list(map(int, line.split(",")))
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if x * log10(a) > largest:
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largest = x * log10(a)
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result = i + 1
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return result
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if __name__ == "__main__":
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print(solution())
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