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* Create TestShiva * Delete TestShiva * Implementation of the Dijkstra-Algorithm in a binary grid * Update double_ended_queue.py * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update least_common_multiple.py * Update sol1.py * Update pyproject.toml * Update pyproject.toml * https://github.com/astral-sh/ruff-pre-commit v0.0.274 --------- Co-authored-by: ShivaDahal99 <130563462+ShivaDahal99@users.noreply.github.com> Co-authored-by: jlhuhn <134317018+jlhuhn@users.noreply.github.com> Co-authored-by: Christian Clauss <cclauss@me.com> Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com>
384 lines
14 KiB
Python
384 lines
14 KiB
Python
"""
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Problem: https://projecteuler.net/problem=54
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In the card game poker, a hand consists of five cards and are ranked,
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from lowest to highest, in the following way:
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High Card: Highest value card.
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One Pair: Two cards of the same value.
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Two Pairs: Two different pairs.
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Three of a Kind: Three cards of the same value.
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Straight: All cards are consecutive values.
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Flush: All cards of the same suit.
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Full House: Three of a kind and a pair.
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Four of a Kind: Four cards of the same value.
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Straight Flush: All cards are consecutive values of same suit.
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Royal Flush: Ten, Jack, Queen, King, Ace, in same suit.
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The cards are valued in the order:
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2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King, Ace.
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If two players have the same ranked hands then the rank made up of the highest
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value wins; for example, a pair of eights beats a pair of fives.
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But if two ranks tie, for example, both players have a pair of queens, then highest
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cards in each hand are compared; if the highest cards tie then the next highest
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cards are compared, and so on.
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The file, poker.txt, contains one-thousand random hands dealt to two players.
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Each line of the file contains ten cards (separated by a single space): the
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first five are Player 1's cards and the last five are Player 2's cards.
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You can assume that all hands are valid (no invalid characters or repeated cards),
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each player's hand is in no specific order, and in each hand there is a clear winner.
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How many hands does Player 1 win?
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Resources used:
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https://en.wikipedia.org/wiki/Texas_hold_%27em
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https://en.wikipedia.org/wiki/List_of_poker_hands
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Similar problem on codewars:
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https://www.codewars.com/kata/ranking-poker-hands
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https://www.codewars.com/kata/sortable-poker-hands
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"""
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from __future__ import annotations
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import os
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class PokerHand:
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"""Create an object representing a Poker Hand based on an input of a
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string which represents the best 5-card combination from the player's hand
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and board cards.
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Attributes: (read-only)
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hand: a string representing the hand consisting of five cards
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Methods:
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compare_with(opponent): takes in player's hand (self) and
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opponent's hand (opponent) and compares both hands according to
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the rules of Texas Hold'em.
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Returns one of 3 strings (Win, Loss, Tie) based on whether
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player's hand is better than the opponent's hand.
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hand_name(): Returns a string made up of two parts: hand name
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and high card.
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Supported operators:
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Rich comparison operators: <, >, <=, >=, ==, !=
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Supported built-in methods and functions:
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list.sort(), sorted()
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"""
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_HAND_NAME = (
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"High card",
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"One pair",
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"Two pairs",
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"Three of a kind",
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"Straight",
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"Flush",
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"Full house",
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"Four of a kind",
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"Straight flush",
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"Royal flush",
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)
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_CARD_NAME = (
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"", # placeholder as tuples are zero-indexed
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"One",
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"Two",
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"Three",
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"Four",
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"Five",
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"Six",
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"Seven",
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"Eight",
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"Nine",
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"Ten",
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"Jack",
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"Queen",
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"King",
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"Ace",
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)
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def __init__(self, hand: str) -> None:
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"""
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Initialize hand.
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Hand should of type str and should contain only five cards each
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separated by a space.
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The cards should be of the following format:
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[card value][card suit]
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The first character is the value of the card:
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2, 3, 4, 5, 6, 7, 8, 9, T(en), J(ack), Q(ueen), K(ing), A(ce)
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The second character represents the suit:
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S(pades), H(earts), D(iamonds), C(lubs)
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For example: "6S 4C KC AS TH"
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"""
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if not isinstance(hand, str):
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msg = f"Hand should be of type 'str': {hand!r}"
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raise TypeError(msg)
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# split removes duplicate whitespaces so no need of strip
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if len(hand.split(" ")) != 5:
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msg = f"Hand should contain only 5 cards: {hand!r}"
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raise ValueError(msg)
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self._hand = hand
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self._first_pair = 0
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self._second_pair = 0
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self._card_values, self._card_suit = self._internal_state()
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self._hand_type = self._get_hand_type()
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self._high_card = self._card_values[0]
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@property
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def hand(self):
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"""Returns the self hand"""
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return self._hand
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def compare_with(self, other: PokerHand) -> str:
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"""
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Determines the outcome of comparing self hand with other hand.
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Returns the output as 'Win', 'Loss', 'Tie' according to the rules of
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Texas Hold'em.
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Here are some examples:
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>>> player = PokerHand("2H 3H 4H 5H 6H") # Stright flush
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>>> opponent = PokerHand("KS AS TS QS JS") # Royal flush
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>>> player.compare_with(opponent)
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'Loss'
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>>> player = PokerHand("2S AH 2H AS AC") # Full house
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>>> opponent = PokerHand("2H 3H 5H 6H 7H") # Flush
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>>> player.compare_with(opponent)
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'Win'
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>>> player = PokerHand("2S AH 4H 5S 6C") # High card
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>>> opponent = PokerHand("AD 4C 5H 6H 2C") # High card
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>>> player.compare_with(opponent)
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'Tie'
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"""
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# Breaking the tie works on the following order of precedence:
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# 1. First pair (default 0)
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# 2. Second pair (default 0)
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# 3. Compare all cards in reverse order because they are sorted.
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# First pair and second pair will only be a non-zero value if the card
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# type is either from the following:
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# 21: Four of a kind
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# 20: Full house
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# 17: Three of a kind
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# 16: Two pairs
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# 15: One pair
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if self._hand_type > other._hand_type:
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return "Win"
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elif self._hand_type < other._hand_type:
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return "Loss"
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elif self._first_pair == other._first_pair:
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if self._second_pair == other._second_pair:
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return self._compare_cards(other)
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else:
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return "Win" if self._second_pair > other._second_pair else "Loss"
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return "Win" if self._first_pair > other._first_pair else "Loss"
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# This function is not part of the problem, I did it just for fun
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def hand_name(self) -> str:
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"""
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Return the name of the hand in the following format:
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'hand name, high card'
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Here are some examples:
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>>> PokerHand("KS AS TS QS JS").hand_name()
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'Royal flush'
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>>> PokerHand("2D 6D 3D 4D 5D").hand_name()
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'Straight flush, Six-high'
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>>> PokerHand("JC 6H JS JD JH").hand_name()
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'Four of a kind, Jacks'
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>>> PokerHand("3D 2H 3H 2C 2D").hand_name()
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'Full house, Twos over Threes'
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>>> PokerHand("2H 4D 3C AS 5S").hand_name() # Low ace
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'Straight, Five-high'
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Source: https://en.wikipedia.org/wiki/List_of_poker_hands
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"""
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name = PokerHand._HAND_NAME[self._hand_type - 14]
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high = PokerHand._CARD_NAME[self._high_card]
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pair1 = PokerHand._CARD_NAME[self._first_pair]
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pair2 = PokerHand._CARD_NAME[self._second_pair]
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if self._hand_type in [22, 19, 18]:
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return name + f", {high}-high"
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elif self._hand_type in [21, 17, 15]:
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return name + f", {pair1}s"
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elif self._hand_type in [20, 16]:
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join = "over" if self._hand_type == 20 else "and"
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return name + f", {pair1}s {join} {pair2}s"
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elif self._hand_type == 23:
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return name
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else:
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return name + f", {high}"
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def _compare_cards(self, other: PokerHand) -> str:
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# Enumerate gives us the index as well as the element of a list
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for index, card_value in enumerate(self._card_values):
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if card_value != other._card_values[index]:
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return "Win" if card_value > other._card_values[index] else "Loss"
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return "Tie"
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def _get_hand_type(self) -> int:
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# Number representing the type of hand internally:
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# 23: Royal flush
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# 22: Straight flush
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# 21: Four of a kind
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# 20: Full house
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# 19: Flush
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# 18: Straight
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# 17: Three of a kind
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# 16: Two pairs
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# 15: One pair
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# 14: High card
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if self._is_flush():
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if self._is_five_high_straight() or self._is_straight():
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return 23 if sum(self._card_values) == 60 else 22
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return 19
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elif self._is_five_high_straight() or self._is_straight():
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return 18
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return 14 + self._is_same_kind()
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def _is_flush(self) -> bool:
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return len(self._card_suit) == 1
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def _is_five_high_straight(self) -> bool:
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# If a card is a five high straight (low ace) change the location of
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# ace from the start of the list to the end. Check whether the first
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# element is ace or not. (Don't want to change again)
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# Five high straight (low ace): AH 2H 3S 4C 5D
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# Why use sorted here? One call to this function will mutate the list to
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# [5, 4, 3, 2, 14] and so for subsequent calls (which will be rare) we
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# need to compare the sorted version.
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# Refer test_multiple_calls_five_high_straight in test_poker_hand.py
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if sorted(self._card_values) == [2, 3, 4, 5, 14]:
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if self._card_values[0] == 14:
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# Remember, our list is sorted in reverse order
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ace_card = self._card_values.pop(0)
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self._card_values.append(ace_card)
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return True
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return False
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def _is_straight(self) -> bool:
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for i in range(4):
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if self._card_values[i] - self._card_values[i + 1] != 1:
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return False
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return True
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def _is_same_kind(self) -> int:
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# Kind Values for internal use:
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# 7: Four of a kind
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# 6: Full house
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# 3: Three of a kind
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# 2: Two pairs
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# 1: One pair
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# 0: False
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kind = val1 = val2 = 0
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for i in range(4):
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# Compare two cards at a time, if they are same increase 'kind',
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# add the value of the card to val1, if it is repeating again we
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# will add 2 to 'kind' as there are now 3 cards with same value.
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# If we get card of different value than val1, we will do the same
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# thing with val2
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if self._card_values[i] == self._card_values[i + 1]:
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if not val1:
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val1 = self._card_values[i]
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kind += 1
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elif val1 == self._card_values[i]:
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kind += 2
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elif not val2:
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val2 = self._card_values[i]
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kind += 1
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elif val2 == self._card_values[i]:
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kind += 2
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# For consistency in hand type (look at note in _get_hand_type function)
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kind = kind + 2 if kind in [4, 5] else kind
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# first meaning first pair to compare in 'compare_with'
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first = max(val1, val2)
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second = min(val1, val2)
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# If it's full house (three count pair + two count pair), make sure
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# first pair is three count and if not then switch them both.
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if kind == 6 and self._card_values.count(first) != 3:
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first, second = second, first
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self._first_pair = first
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self._second_pair = second
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return kind
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def _internal_state(self) -> tuple[list[int], set[str]]:
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# Internal representation of hand as a list of card values and
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# a set of card suit
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trans: dict = {"T": "10", "J": "11", "Q": "12", "K": "13", "A": "14"}
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new_hand = self._hand.translate(str.maketrans(trans)).split()
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card_values = [int(card[:-1]) for card in new_hand]
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card_suit = {card[-1] for card in new_hand}
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return sorted(card_values, reverse=True), card_suit
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def __repr__(self):
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return f'{self.__class__}("{self._hand}")'
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def __str__(self):
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return self._hand
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# Rich comparison operators (used in list.sort() and sorted() builtin functions)
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# Note that this is not part of the problem but another extra feature where
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# if you have a list of PokerHand objects, you can sort them just through
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# the builtin functions.
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def __eq__(self, other):
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if isinstance(other, PokerHand):
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return self.compare_with(other) == "Tie"
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return NotImplemented
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def __lt__(self, other):
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if isinstance(other, PokerHand):
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return self.compare_with(other) == "Loss"
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return NotImplemented
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def __le__(self, other):
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if isinstance(other, PokerHand):
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return self < other or self == other
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return NotImplemented
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def __gt__(self, other):
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if isinstance(other, PokerHand):
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return not self < other and self != other
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return NotImplemented
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def __ge__(self, other):
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if isinstance(other, PokerHand):
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return not self < other
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return NotImplemented
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def __hash__(self):
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return object.__hash__(self)
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def solution() -> int:
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# Solution for problem number 54 from Project Euler
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# Input from poker_hands.txt file
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answer = 0
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script_dir = os.path.abspath(os.path.dirname(__file__))
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poker_hands = os.path.join(script_dir, "poker_hands.txt")
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with open(poker_hands) as file_hand:
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for line in file_hand:
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player_hand = line[:14].strip()
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opponent_hand = line[15:].strip()
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player, opponent = PokerHand(player_hand), PokerHand(opponent_hand)
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output = player.compare_with(opponent)
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if output == "Win":
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answer += 1
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return answer
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if __name__ == "__main__":
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solution()
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