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205 lines
7.0 KiB
Python
205 lines
7.0 KiB
Python
"""
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Implementation of a basic regression decision tree.
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Input data set: The input data set must be 1-dimensional with continuous labels.
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Output: The decision tree maps a real number input to a real number output.
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"""
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import numpy as np
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class DecisionTree:
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def __init__(self, depth=5, min_leaf_size=5):
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self.depth = depth
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self.decision_boundary = 0
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self.left = None
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self.right = None
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self.min_leaf_size = min_leaf_size
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self.prediction = None
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def mean_squared_error(self, labels, prediction):
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"""
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mean_squared_error:
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@param labels: a one-dimensional numpy array
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@param prediction: a floating point value
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return value: mean_squared_error calculates the error if prediction is used to
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estimate the labels
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>>> tester = DecisionTree()
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>>> test_labels = np.array([1,2,3,4,5,6,7,8,9,10])
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>>> test_prediction = float(6)
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>>> tester.mean_squared_error(test_labels, test_prediction) == (
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... TestDecisionTree.helper_mean_squared_error_test(test_labels,
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... test_prediction))
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True
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>>> test_labels = np.array([1,2,3])
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>>> test_prediction = float(2)
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>>> tester.mean_squared_error(test_labels, test_prediction) == (
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... TestDecisionTree.helper_mean_squared_error_test(test_labels,
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... test_prediction))
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True
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"""
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if labels.ndim != 1:
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print("Error: Input labels must be one dimensional")
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return np.mean((labels - prediction) ** 2)
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def train(self, x, y):
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"""
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train:
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@param x: a one-dimensional numpy array
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@param y: a one-dimensional numpy array.
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The contents of y are the labels for the corresponding X values
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train() does not have a return value
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Examples:
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1. Try to train when x & y are of same length & 1 dimensions (No errors)
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>>> dt = DecisionTree()
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>>> dt.train(np.array([10,20,30,40,50]),np.array([0,0,0,1,1]))
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2. Try to train when x is 2 dimensions
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>>> dt = DecisionTree()
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>>> dt.train(np.array([[1,2,3,4,5],[1,2,3,4,5]]),np.array([0,0,0,1,1]))
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Traceback (most recent call last):
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...
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ValueError: Input data set must be one-dimensional
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3. Try to train when x and y are not of the same length
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>>> dt = DecisionTree()
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>>> dt.train(np.array([1,2,3,4,5]),np.array([[0,0,0,1,1],[0,0,0,1,1]]))
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Traceback (most recent call last):
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...
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ValueError: x and y have different lengths
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4. Try to train when x & y are of the same length but different dimensions
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>>> dt = DecisionTree()
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>>> dt.train(np.array([1,2,3,4,5]),np.array([[1],[2],[3],[4],[5]]))
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Traceback (most recent call last):
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...
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ValueError: Data set labels must be one-dimensional
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This section is to check that the inputs conform to our dimensionality
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constraints
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"""
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if x.ndim != 1:
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raise ValueError("Input data set must be one-dimensional")
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if len(x) != len(y):
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raise ValueError("x and y have different lengths")
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if y.ndim != 1:
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raise ValueError("Data set labels must be one-dimensional")
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if len(x) < 2 * self.min_leaf_size:
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self.prediction = np.mean(y)
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return
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if self.depth == 1:
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self.prediction = np.mean(y)
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return
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best_split = 0
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min_error = self.mean_squared_error(x, np.mean(y)) * 2
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"""
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loop over all possible splits for the decision tree. find the best split.
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if no split exists that is less than 2 * error for the entire array
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then the data set is not split and the average for the entire array is used as
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the predictor
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"""
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for i in range(len(x)):
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if len(x[:i]) < self.min_leaf_size:
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continue
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elif len(x[i:]) < self.min_leaf_size:
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continue
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else:
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error_left = self.mean_squared_error(x[:i], np.mean(y[:i]))
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error_right = self.mean_squared_error(x[i:], np.mean(y[i:]))
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error = error_left + error_right
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if error < min_error:
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best_split = i
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min_error = error
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if best_split != 0:
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left_x = x[:best_split]
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left_y = y[:best_split]
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right_x = x[best_split:]
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right_y = y[best_split:]
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self.decision_boundary = x[best_split]
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self.left = DecisionTree(
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depth=self.depth - 1, min_leaf_size=self.min_leaf_size
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)
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self.right = DecisionTree(
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depth=self.depth - 1, min_leaf_size=self.min_leaf_size
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)
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self.left.train(left_x, left_y)
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self.right.train(right_x, right_y)
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else:
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self.prediction = np.mean(y)
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return
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def predict(self, x):
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"""
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predict:
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@param x: a floating point value to predict the label of
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the prediction function works by recursively calling the predict function
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of the appropriate subtrees based on the tree's decision boundary
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"""
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if self.prediction is not None:
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return self.prediction
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elif self.left or self.right is not None:
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if x >= self.decision_boundary:
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return self.right.predict(x)
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else:
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return self.left.predict(x)
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else:
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print("Error: Decision tree not yet trained")
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return None
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class TestDecisionTree:
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"""Decision Tres test class"""
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@staticmethod
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def helper_mean_squared_error_test(labels, prediction):
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"""
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helper_mean_squared_error_test:
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@param labels: a one dimensional numpy array
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@param prediction: a floating point value
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return value: helper_mean_squared_error_test calculates the mean squared error
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"""
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squared_error_sum = float(0)
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for label in labels:
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squared_error_sum += (label - prediction) ** 2
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return float(squared_error_sum / labels.size)
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def main():
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"""
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In this demonstration we're generating a sample data set from the sin function in
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numpy. We then train a decision tree on the data set and use the decision tree to
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predict the label of 10 different test values. Then the mean squared error over
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this test is displayed.
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"""
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x = np.arange(-1.0, 1.0, 0.005)
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y = np.sin(x)
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tree = DecisionTree(depth=10, min_leaf_size=10)
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tree.train(x, y)
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rng = np.random.default_rng()
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test_cases = (rng.random(10) * 2) - 1
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predictions = np.array([tree.predict(x) for x in test_cases])
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avg_error = np.mean((predictions - test_cases) ** 2)
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print("Test values: " + str(test_cases))
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print("Predictions: " + str(predictions))
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print("Average error: " + str(avg_error))
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if __name__ == "__main__":
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main()
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import doctest
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doctest.testmod(name="mean_squarred_error", verbose=True)
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