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* Update knuth_morris_pratt.py - changed Boolean to Index * Update knuth_morris_pratt.py * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update knuth_morris_pratt.py * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update knuth_morris_pratt.py * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Update back_propagation_neural_network.py * Update back_propagation_neural_network.py * Update strings/knuth_morris_pratt.py * Update knuth_morris_pratt.py * Update knuth_morris_pratt.py --------- Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Christian Clauss <cclauss@me.com>
101 lines
2.6 KiB
Python
101 lines
2.6 KiB
Python
from __future__ import annotations
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def knuth_morris_pratt(text: str, pattern: str) -> int:
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"""
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The Knuth-Morris-Pratt Algorithm for finding a pattern within a piece of text
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with complexity O(n + m)
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1) Preprocess pattern to identify any suffixes that are identical to prefixes
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This tells us where to continue from if we get a mismatch between a character
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in our pattern and the text.
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2) Step through the text one character at a time and compare it to a character in
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the pattern updating our location within the pattern if necessary
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>>> kmp = "knuth_morris_pratt"
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>>> all(
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... knuth_morris_pratt(kmp, s) == kmp.find(s)
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... for s in ("kn", "h_m", "rr", "tt", "not there")
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... )
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True
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"""
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# 1) Construct the failure array
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failure = get_failure_array(pattern)
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# 2) Step through text searching for pattern
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i, j = 0, 0 # index into text, pattern
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while i < len(text):
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if pattern[j] == text[i]:
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if j == (len(pattern) - 1):
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return i - j
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j += 1
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# if this is a prefix in our pattern
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# just go back far enough to continue
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elif j > 0:
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j = failure[j - 1]
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continue
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i += 1
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return -1
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def get_failure_array(pattern: str) -> list[int]:
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"""
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Calculates the new index we should go to if we fail a comparison
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:param pattern:
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:return:
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"""
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failure = [0]
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i = 0
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j = 1
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while j < len(pattern):
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if pattern[i] == pattern[j]:
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i += 1
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elif i > 0:
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i = failure[i - 1]
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continue
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j += 1
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failure.append(i)
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return failure
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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# Test 1)
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pattern = "abc1abc12"
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text1 = "alskfjaldsabc1abc1abc12k23adsfabcabc"
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text2 = "alskfjaldsk23adsfabcabc"
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assert knuth_morris_pratt(text1, pattern) and knuth_morris_pratt(text2, pattern)
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# Test 2)
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pattern = "ABABX"
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text = "ABABZABABYABABX"
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assert knuth_morris_pratt(text, pattern)
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# Test 3)
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pattern = "AAAB"
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text = "ABAAAAAB"
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assert knuth_morris_pratt(text, pattern)
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# Test 4)
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pattern = "abcdabcy"
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text = "abcxabcdabxabcdabcdabcy"
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assert knuth_morris_pratt(text, pattern)
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# Test 5) -> Doctests
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kmp = "knuth_morris_pratt"
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assert all(
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knuth_morris_pratt(kmp, s) == kmp.find(s)
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for s in ("kn", "h_m", "rr", "tt", "not there")
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)
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# Test 6)
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pattern = "aabaabaaa"
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assert get_failure_array(pattern) == [0, 1, 0, 1, 2, 3, 4, 5, 2]
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