Python/searches/sentinel_linear_search.py
Christian Clauss 47a9ea2b0b
Simplify code by dropping support for legacy Python (#1143)
* Simplify code by dropping support for legacy Python

* sort() --> sorted()
2019-08-19 15:37:49 +02:00

57 lines
1.4 KiB
Python

"""
This is pure python implementation of sentinel linear search algorithm
For doctests run following command:
python -m doctest -v sentinel_linear_search.py
or
python3 -m doctest -v sentinel_linear_search.py
For manual testing run:
python sentinel_linear_search.py
"""
def sentinel_linear_search(sequence, target):
"""Pure implementation of sentinel linear search algorithm in Python
:param sequence: some sequence with comparable items
:param target: item value to search
:return: index of found item or None if item is not found
Examples:
>>> sentinel_linear_search([0, 5, 7, 10, 15], 0)
0
>>> sentinel_linear_search([0, 5, 7, 10, 15], 15)
4
>>> sentinel_linear_search([0, 5, 7, 10, 15], 5)
1
>>> sentinel_linear_search([0, 5, 7, 10, 15], 6)
"""
sequence.append(target)
index = 0
while sequence[index] != target:
index += 1
sequence.pop()
if index == len(sequence):
return None
return index
if __name__ == '__main__':
user_input = input('Enter numbers separated by comma:\n').strip()
sequence = [int(item) for item in user_input.split(',')]
target_input = input('Enter a single number to be found in the list:\n')
target = int(target_input)
result = sentinel_linear_search(sequence, target)
if result is not None:
print('{} found at positions: {}'.format(target, result))
else:
print('Not found')