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46 lines
1.2 KiB
Python
46 lines
1.2 KiB
Python
"""
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The function below will convert any binary string to the octal equivalent.
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>>> bin_to_octal("1111")
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'17'
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>>> bin_to_octal("101010101010011")
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'52523'
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>>> bin_to_octal("")
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Traceback (most recent call last):
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...
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ValueError: Empty string was passed to the function
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>>> bin_to_octal("a-1")
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Traceback (most recent call last):
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...
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ValueError: Non-binary value was passed to the function
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"""
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def bin_to_octal(bin_string: str) -> str:
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if not all(char in "01" for char in bin_string):
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raise ValueError("Non-binary value was passed to the function")
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if not bin_string:
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raise ValueError("Empty string was passed to the function")
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oct_string = ""
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while len(bin_string) % 3 != 0:
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bin_string = "0" + bin_string
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bin_string_in_3_list = [
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bin_string[index : index + 3]
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for index in range(len(bin_string))
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if index % 3 == 0
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]
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for bin_group in bin_string_in_3_list:
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oct_val = 0
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for index, val in enumerate(bin_group):
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oct_val += int(2 ** (2 - index) * int(val))
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oct_string += str(oct_val)
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return oct_string
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if __name__ == "__main__":
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from doctest import testmod
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testmod()
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