Python/strings/is_palindrome.py
Christian Clauss 64543faa98
Make some ruff fixes (#8154)
* Make some ruff fixes

* Undo manual fix

* Undo manual fix

* Updates from ruff=0.0.251
2023-03-01 17:23:33 +01:00

42 lines
1.3 KiB
Python

def is_palindrome(s: str) -> bool:
"""
Determine if the string s is a palindrome.
>>> is_palindrome("A man, A plan, A canal -- Panama!")
True
>>> is_palindrome("Hello")
False
>>> is_palindrome("Able was I ere I saw Elba")
True
>>> is_palindrome("racecar")
True
>>> is_palindrome("Mr. Owl ate my metal worm?")
True
"""
# Since punctuation, capitalization, and spaces are often ignored while checking
# palindromes, we first remove them from our string.
s = "".join(character for character in s.lower() if character.isalnum())
# return s == s[::-1] the slicing method
# uses extra spaces we can
# better with iteration method.
end = len(s) // 2
n = len(s)
# We need to traverse till half of the length of string
# as we can get access of the i'th last element from
# i'th index.
# eg: [0,1,2,3,4,5] => 4th index can be accessed
# with the help of 1st index (i==n-i-1)
# where n is length of string
return all(s[i] == s[n - i - 1] for i in range(end))
if __name__ == "__main__":
s = input("Please enter a string to see if it is a palindrome: ")
if is_palindrome(s):
print(f"'{s}' is a palindrome.")
else:
print(f"'{s}' is not a palindrome.")