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* Create sol1.py * Create __init__.py * Update sol1.py * corrected range * Add files via upload * Update DIRECTORY.md * Create sol1.py * Update sol1.py * Create __init__.py * Update DIRECTORY.md * Delete isotonic.py * Update sol1.py * Problem_27_project_euler * project_euler/Problem_27/sol1.py * project_euler/Problem_27/sol1.py * project_euler/problem_27/ * project_euler/problem_27 * project_euler/problem_27 * update sol1 of Euler Problem 27 solution script Added * Remove slow test, wrap long comments, format with psf/black * Delete __init__.py * Add type hints * Add doctests to function is_prime() * Rename project_euler/problem_27/project_euler/problem_27/sol1.pysol1.py to project_euler/problem_27/problem_27_sol1.py * Added Problem 33 * added solution 1 for problem_99 * update added solution 1 for problem_99 * update * Update sol1.py
34 lines
1.0 KiB
Python
34 lines
1.0 KiB
Python
"""
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Problem:
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Comparing two numbers written in index form like 2'11 and 3'7 is not difficult, as any calculator would confirm that 2^11 = 2048 < 3^7 = 2187.
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However, confirming that 632382^518061 > 519432^525806 would be much more difficult, as both numbers contain over three million digits.
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Using base_exp.txt, a 22K text file containing one thousand lines with a base/exponent pair on each line, determine which line number has the greatest numerical value.
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NOTE: The first two lines in the file represent the numbers in the example given above.
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"""
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import os
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from math import log10
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def find_largest(data_file: str="base_exp.txt") -> int:
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"""
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>>> find_largest()
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709
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"""
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largest = [0, 0]
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for i, line in enumerate(
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open(os.path.join(os.path.dirname(__file__), data_file))
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):
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a, x = list(map(int, line.split(",")))
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if x * log10(a) > largest[0]:
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largest = [x * log10(a), i + 1]
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return largest[1]
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if __name__ == "__main__":
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print(find_largest())
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