mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-11-24 13:31:07 +00:00
267b5eff40
* Added doctest and more explanation about Dijkstra execution. * tests were not passing with python2 due to missing __init__.py file at number_theory folder * Removed the dot at the beginning of the imported modules names because 'python3 -m doctest -v data_structures/hashing/*.py' and 'python3 -m doctest -v data_structures/stacks/*.py' were failing not finding hash_table.py and stack.py modules. * Moved global code to main scope and added doctest for project euler problems 1 to 14. * Added test case for negative input. * Changed N variable to do not use end of line scape because in case there is a space after it the script will break making it much more error prone. * Added problems description and doctests to the ones that were missing. Limited line length to 79 and executed python black over all scripts. * Changed the way files are loaded to support pytest call. * Added __init__.py to problems to make them modules and allow pytest execution. * Added project_euler folder to test units execution * Changed 'os.path.split(os.path.realpath(__file__))' to 'os.path.dirname()'
72 lines
1.4 KiB
Python
72 lines
1.4 KiB
Python
# -*- coding: utf-8 -*-
|
||
"""
|
||
Coin sums
|
||
Problem 31
|
||
In England the currency is made up of pound, £, and pence, p, and there are
|
||
eight coins in general circulation:
|
||
|
||
1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p).
|
||
It is possible to make £2 in the following way:
|
||
|
||
1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p
|
||
How many different ways can £2 be made using any number of coins?
|
||
"""
|
||
from __future__ import print_function
|
||
|
||
try:
|
||
raw_input # Python 2
|
||
except NameError:
|
||
raw_input = input # Python 3
|
||
|
||
|
||
def one_pence():
|
||
return 1
|
||
|
||
|
||
def two_pence(x):
|
||
return 0 if x < 0 else two_pence(x - 2) + one_pence()
|
||
|
||
|
||
def five_pence(x):
|
||
return 0 if x < 0 else five_pence(x - 5) + two_pence(x)
|
||
|
||
|
||
def ten_pence(x):
|
||
return 0 if x < 0 else ten_pence(x - 10) + five_pence(x)
|
||
|
||
|
||
def twenty_pence(x):
|
||
return 0 if x < 0 else twenty_pence(x - 20) + ten_pence(x)
|
||
|
||
|
||
def fifty_pence(x):
|
||
return 0 if x < 0 else fifty_pence(x - 50) + twenty_pence(x)
|
||
|
||
|
||
def one_pound(x):
|
||
return 0 if x < 0 else one_pound(x - 100) + fifty_pence(x)
|
||
|
||
|
||
def two_pound(x):
|
||
return 0 if x < 0 else two_pound(x - 200) + one_pound(x)
|
||
|
||
|
||
def solution(n):
|
||
"""Returns the number of different ways can £n be made using any number of
|
||
coins?
|
||
|
||
>>> solution(500)
|
||
6295434
|
||
>>> solution(200)
|
||
73682
|
||
>>> solution(50)
|
||
451
|
||
>>> solution(10)
|
||
11
|
||
"""
|
||
return two_pound(n)
|
||
|
||
|
||
if __name__ == "__main__":
|
||
print(solution(int(str(input()).strip())))
|