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* Python mirror_formulae.py is added to the repository * Changes done after reading readme.md * Changes for running doctest on all platforms * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Change 2 for Doctests * Changes for doctest 2 * updating DIRECTORY.md * Doctest whitespace error rectification to mirror_formulae.py * updating DIRECTORY.md * Adding Thermodynamic Work Done Formulae * Work done on/by body in a thermodynamic setting * updating DIRECTORY.md * updating DIRECTORY.md * Doctest adiition to binary_exponentiation_3.py * Change 1 * updating DIRECTORY.md * Rename binary_exponentiation_3.py to binary_exponentiation_2.py * updating DIRECTORY.md * updating DIRECTORY.md * Formatting --------- Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com> Co-authored-by: Christian Clauss <cclauss@me.com> Co-authored-by: Tianyi Zheng <tianyizheng02@gmail.com>
62 lines
1.3 KiB
Python
62 lines
1.3 KiB
Python
"""
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Binary Exponentiation
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This is a method to find a^b in O(log b) time complexity
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This is one of the most commonly used methods of exponentiation
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It's also useful when the solution to (a^b) % c is required because a, b, c may be
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over the computer's calculation limits
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Let's say you need to calculate a ^ b
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- RULE 1 : a ^ b = (a*a) ^ (b/2) ---- example : 4 ^ 4 = (4*4) ^ (4/2) = 16 ^ 2
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- RULE 2 : IF b is odd, then a ^ b = a * (a ^ (b - 1)), where b - 1 is even
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Once b is even, repeat the process until b = 1 or b = 0, because a^1 = a and a^0 = 1
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For modular exponentiation, we use the fact that (a*b) % c = ((a%c) * (b%c)) % c
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Now apply RULE 1 or 2 as required
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@author chinmoy159
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"""
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def b_expo(a: int, b: int) -> int:
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"""
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>>> b_expo(2, 10)
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1024
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>>> b_expo(9, 0)
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1
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>>> b_expo(0, 12)
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0
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>>> b_expo(4, 12)
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16777216
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"""
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res = 1
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while b > 0:
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if b & 1:
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res *= a
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a *= a
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b >>= 1
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return res
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def b_expo_mod(a: int, b: int, c: int) -> int:
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"""
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>>> b_expo_mod(2, 10, 1000000007)
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1024
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>>> b_expo_mod(11, 13, 19)
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11
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>>> b_expo_mod(0, 19, 20)
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0
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>>> b_expo_mod(15, 5, 4)
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3
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"""
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res = 1
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while b > 0:
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if b & 1:
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res = ((res % c) * (a % c)) % c
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a *= a
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b >>= 1
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return res
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