mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-12-05 02:40:16 +00:00
0992498a10
All the operation is being done in an else condition for "if number >= 0"
110 lines
3.3 KiB
Python
110 lines
3.3 KiB
Python
# Information on binary shifts:
|
|
# https://docs.python.org/3/library/stdtypes.html#bitwise-operations-on-integer-types
|
|
# https://www.interviewcake.com/concept/java/bit-shift
|
|
|
|
|
|
def logical_left_shift(number: int, shift_amount: int) -> str:
|
|
"""
|
|
Take in 2 positive integers.
|
|
'number' is the integer to be logically left shifted 'shift_amount' times.
|
|
i.e. (number << shift_amount)
|
|
Return the shifted binary representation.
|
|
|
|
>>> logical_left_shift(0, 1)
|
|
'0b00'
|
|
>>> logical_left_shift(1, 1)
|
|
'0b10'
|
|
>>> logical_left_shift(1, 5)
|
|
'0b100000'
|
|
>>> logical_left_shift(17, 2)
|
|
'0b1000100'
|
|
>>> logical_left_shift(1983, 4)
|
|
'0b111101111110000'
|
|
>>> logical_left_shift(1, -1)
|
|
Traceback (most recent call last):
|
|
...
|
|
ValueError: both inputs must be positive integers
|
|
"""
|
|
if number < 0 or shift_amount < 0:
|
|
raise ValueError("both inputs must be positive integers")
|
|
|
|
binary_number = str(bin(number))
|
|
binary_number += "0" * shift_amount
|
|
return binary_number
|
|
|
|
|
|
def logical_right_shift(number: int, shift_amount: int) -> str:
|
|
"""
|
|
Take in positive 2 integers.
|
|
'number' is the integer to be logically right shifted 'shift_amount' times.
|
|
i.e. (number >>> shift_amount)
|
|
Return the shifted binary representation.
|
|
|
|
>>> logical_right_shift(0, 1)
|
|
'0b0'
|
|
>>> logical_right_shift(1, 1)
|
|
'0b0'
|
|
>>> logical_right_shift(1, 5)
|
|
'0b0'
|
|
>>> logical_right_shift(17, 2)
|
|
'0b100'
|
|
>>> logical_right_shift(1983, 4)
|
|
'0b1111011'
|
|
>>> logical_right_shift(1, -1)
|
|
Traceback (most recent call last):
|
|
...
|
|
ValueError: both inputs must be positive integers
|
|
"""
|
|
if number < 0 or shift_amount < 0:
|
|
raise ValueError("both inputs must be positive integers")
|
|
|
|
binary_number = str(bin(number))[2:]
|
|
if shift_amount >= len(binary_number):
|
|
return "0b0"
|
|
shifted_binary_number = binary_number[: len(binary_number) - shift_amount]
|
|
return "0b" + shifted_binary_number
|
|
|
|
|
|
def arithmetic_right_shift(number: int, shift_amount: int) -> str:
|
|
"""
|
|
Take in 2 integers.
|
|
'number' is the integer to be arithmetically right shifted 'shift_amount' times.
|
|
i.e. (number >> shift_amount)
|
|
Return the shifted binary representation.
|
|
|
|
>>> arithmetic_right_shift(0, 1)
|
|
'0b00'
|
|
>>> arithmetic_right_shift(1, 1)
|
|
'0b00'
|
|
>>> arithmetic_right_shift(-1, 1)
|
|
'0b11'
|
|
>>> arithmetic_right_shift(17, 2)
|
|
'0b000100'
|
|
>>> arithmetic_right_shift(-17, 2)
|
|
'0b111011'
|
|
>>> arithmetic_right_shift(-1983, 4)
|
|
'0b111110000100'
|
|
"""
|
|
if number >= 0: # Get binary representation of positive number
|
|
binary_number = "0" + str(bin(number)).strip("-")[2:]
|
|
else: # Get binary (2's complement) representation of negative number
|
|
binary_number_length = len(bin(number)[3:]) # Find 2's complement of number
|
|
binary_number = bin(abs(number) - (1 << binary_number_length))[3:]
|
|
binary_number = (
|
|
"1" + "0" * (binary_number_length - len(binary_number)) + binary_number
|
|
)
|
|
|
|
if shift_amount >= len(binary_number):
|
|
return "0b" + binary_number[0] * len(binary_number)
|
|
return (
|
|
"0b"
|
|
+ binary_number[0] * shift_amount
|
|
+ binary_number[: len(binary_number) - shift_amount]
|
|
)
|
|
|
|
|
|
if __name__ == "__main__":
|
|
import doctest
|
|
|
|
doctest.testmod()
|