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* fix: space count in strings/word_occurrence.py * Update strings/word_occurrence.py Co-Authored-By: Christian Clauss <cclauss@me.com> * Update strings/word_occurrence.py Co-Authored-By: Christian Clauss <cclauss@me.com> * Update strings/word_occurrence.py Co-Authored-By: Christian Clauss <cclauss@me.com> * Update word_occurrence.py Seems like, there is no need o `occurrence.pop('', None)` Co-authored-by: Christian Clauss <cclauss@me.com>
27 lines
843 B
Python
27 lines
843 B
Python
# Created by sarathkaul on 17/11/19
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# Modified by Arkadip Bhattacharya(@darkmatter18) on 20/04/2020
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from collections import defaultdict
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def word_occurence(sentence: str) -> dict:
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"""
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>>> from collections import Counter
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>>> SENTENCE = "a b A b c b d b d e f e g e h e i e j e 0"
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>>> occurence_dict = word_occurence(SENTENCE)
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>>> all(occurence_dict[word] == count for word, count
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... in Counter(SENTENCE.split()).items())
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True
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>>> dict(word_occurence("Two spaces"))
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{'Two': 1, 'spaces': 1}
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"""
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occurrence = defaultdict(int)
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# Creating a dictionary containing count of each word
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for word in sentence.split():
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occurrence[word] += 1
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return occurrence
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if __name__ == "__main__":
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for word, count in word_occurence("INPUT STRING").items():
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print(f"{word}: {count}")
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