Python/other/nested_brackets.py
Christian Clauss 47a9ea2b0b
Simplify code by dropping support for legacy Python (#1143)
* Simplify code by dropping support for legacy Python

* sort() --> sorted()
2019-08-19 15:37:49 +02:00

48 lines
1.2 KiB
Python

'''
The nested brackets problem is a problem that determines if a sequence of
brackets are properly nested. A sequence of brackets s is considered properly nested
if any of the following conditions are true:
- s is empty
- s has the form (U) or [U] or {U} where U is a properly nested string
- s has the form VW where V and W are properly nested strings
For example, the string "()()[()]" is properly nested but "[(()]" is not.
The function called is_balanced takes as input a string S which is a sequence of brackets and
returns true if S is nested and false otherwise.
'''
def is_balanced(S):
stack = []
open_brackets = set({'(', '[', '{'})
closed_brackets = set({')', ']', '}'})
open_to_closed = dict({'{':'}', '[':']', '(':')'})
for i in range(len(S)):
if S[i] in open_brackets:
stack.append(S[i])
elif S[i] in closed_brackets:
if len(stack) == 0 or (len(stack) > 0 and open_to_closed[stack.pop()] != S[i]):
return False
return len(stack) == 0
def main():
S = input("Enter sequence of brackets: ")
if is_balanced(S):
print((S, "is balanced"))
else:
print((S, "is not balanced"))
if __name__ == "__main__":
main()