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140 lines
4.7 KiB
Python
140 lines
4.7 KiB
Python
"""
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Implementation of a basic regression decision tree.
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Input data set: The input data set must be 1-dimensional with continuous labels.
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Output: The decision tree maps a real number input to a real number output.
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"""
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from __future__ import print_function
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import numpy as np
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class Decision_Tree:
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def __init__(self, depth = 5, min_leaf_size = 5):
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self.depth = depth
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self.decision_boundary = 0
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self.left = None
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self.right = None
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self.min_leaf_size = min_leaf_size
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self.prediction = None
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def mean_squared_error(self, labels, prediction):
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"""
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mean_squared_error:
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@param labels: a one dimensional numpy array
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@param prediction: a floating point value
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return value: mean_squared_error calculates the error if prediction is used to estimate the labels
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"""
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if labels.ndim != 1:
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print("Error: Input labels must be one dimensional")
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return np.mean((labels - prediction) ** 2)
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def train(self, X, y):
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"""
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train:
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@param X: a one dimensional numpy array
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@param y: a one dimensional numpy array.
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The contents of y are the labels for the corresponding X values
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train does not have a return value
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"""
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"""
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this section is to check that the inputs conform to our dimensionality constraints
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"""
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if X.ndim != 1:
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print("Error: Input data set must be one dimensional")
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return
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if len(X) != len(y):
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print("Error: X and y have different lengths")
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return
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if y.ndim != 1:
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print("Error: Data set labels must be one dimensional")
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return
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if len(X) < 2 * self.min_leaf_size:
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self.prediction = np.mean(y)
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return
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if self.depth == 1:
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self.prediction = np.mean(y)
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return
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best_split = 0
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min_error = self.mean_squared_error(X,np.mean(y)) * 2
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"""
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loop over all possible splits for the decision tree. find the best split.
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if no split exists that is less than 2 * error for the entire array
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then the data set is not split and the average for the entire array is used as the predictor
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"""
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for i in range(len(X)):
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if len(X[:i]) < self.min_leaf_size:
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continue
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elif len(X[i:]) < self.min_leaf_size:
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continue
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else:
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error_left = self.mean_squared_error(X[:i], np.mean(y[:i]))
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error_right = self.mean_squared_error(X[i:], np.mean(y[i:]))
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error = error_left + error_right
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if error < min_error:
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best_split = i
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min_error = error
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if best_split != 0:
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left_X = X[:best_split]
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left_y = y[:best_split]
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right_X = X[best_split:]
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right_y = y[best_split:]
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self.decision_boundary = X[best_split]
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self.left = Decision_Tree(depth = self.depth - 1, min_leaf_size = self.min_leaf_size)
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self.right = Decision_Tree(depth = self.depth - 1, min_leaf_size = self.min_leaf_size)
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self.left.train(left_X, left_y)
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self.right.train(right_X, right_y)
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else:
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self.prediction = np.mean(y)
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return
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def predict(self, x):
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"""
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predict:
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@param x: a floating point value to predict the label of
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the prediction function works by recursively calling the predict function
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of the appropriate subtrees based on the tree's decision boundary
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"""
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if self.prediction is not None:
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return self.prediction
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elif self.left or self.right is not None:
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if x >= self.decision_boundary:
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return self.right.predict(x)
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else:
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return self.left.predict(x)
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else:
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print("Error: Decision tree not yet trained")
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return None
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def main():
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"""
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In this demonstration we're generating a sample data set from the sin function in numpy.
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We then train a decision tree on the data set and use the decision tree to predict the
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label of 10 different test values. Then the mean squared error over this test is displayed.
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"""
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X = np.arange(-1., 1., 0.005)
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y = np.sin(X)
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tree = Decision_Tree(depth = 10, min_leaf_size = 10)
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tree.train(X,y)
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test_cases = (np.random.rand(10) * 2) - 1
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predictions = np.array([tree.predict(x) for x in test_cases])
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avg_error = np.mean((predictions - test_cases) ** 2)
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print("Test values: " + str(test_cases))
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print("Predictions: " + str(predictions))
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print("Average error: " + str(avg_error))
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if __name__ == '__main__':
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main() |