Python/matrix/count_islands_in_matrix.py
Muhammadrasul 4a2d457747
Count (#2084)
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* Update matrix/count_islands_in_matrix.py

Co-authored-by: Christian Clauss <cclauss@me.com>

* Update matrix/count_islands_in_matrix.py

Co-authored-by: Christian Clauss <cclauss@me.com>

* Update matrix/count_islands_in_matrix.py

Co-authored-by: Christian Clauss <cclauss@me.com>

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* Update count_islands_in_matrix.py

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Co-authored-by: Christian Clauss <cclauss@me.com>
2020-06-16 14:36:09 +02:00

37 lines
1.4 KiB
Python

# An island in matrix is a group of linked areas, all having the same value.
# This code counts number of islands in a given matrix, with including diagonal
# connections.
class matrix: # Public class to implement a graph
def __init__(self, row: int, col: int, graph: list):
self.ROW = row
self.COL = col
self.graph = graph
def is_safe(self, i, j, visited) -> bool:
return (
0 <= i < self.ROW
and 0 <= j < self.COL
and not visited[i][j]
and self.graph[i][j]
)
def diffs(self, i, j, visited): # Checking all 8 elements surrounding nth element
rowNbr = [-1, -1, -1, 0, 0, 1, 1, 1] # Coordinate order
colNbr = [-1, 0, 1, -1, 1, -1, 0, 1]
visited[i][j] = True # Make those cells visited
for k in range(8):
if self.is_safe(i + rowNbr[k], j + colNbr[k], visited):
self.diffs(i + rowNbr[k], j + colNbr[k], visited)
def count_islands(self) -> int: # And finally, count all islands.
visited = [[False for j in range(self.COL)] for i in range(self.ROW)]
count = 0
for i in range(self.ROW):
for j in range(self.COL):
if visited[i][j] is False and self.graph[i][j] == 1:
self.diffs(i, j, visited)
count += 1
return count