Python/graphs/check_bipartite_graph_bfs.py
Christian Clauss 1f8a21d727
Tighten up psf/black and flake8 (#2024)
* Tighten up psf/black and flake8

* Fix some tests

* Fix some E741

* Fix some E741

* updating DIRECTORY.md

Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
2020-05-22 08:10:11 +02:00

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1.3 KiB
Python

# Check whether Graph is Bipartite or Not using BFS
# A Bipartite Graph is a graph whose vertices can be divided into two independent sets,
# U and V such that every edge (u, v) either connects a vertex from U to V or a vertex
# from V to U. In other words, for every edge (u, v), either u belongs to U and v to V,
# or u belongs to V and v to U. We can also say that there is no edge that connects
# vertices of same set.
def checkBipartite(graph):
queue = []
visited = [False] * len(graph)
color = [-1] * len(graph)
def bfs():
while queue:
u = queue.pop(0)
visited[u] = True
for neighbour in graph[u]:
if neighbour == u:
return False
if color[neighbour] == -1:
color[neighbour] = 1 - color[u]
queue.append(neighbour)
elif color[neighbour] == color[u]:
return False
return True
for i in range(len(graph)):
if not visited[i]:
queue.append(i)
color[i] = 0
if bfs() is False:
return False
return True
if __name__ == "__main__":
# Adjacency List of graph
print(checkBipartite({0: [1, 3], 1: [0, 2], 2: [1, 3], 3: [0, 2]}))