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4700297b3e
* Enable ruff RUF002 rule * Fix --------- Co-authored-by: Christian Clauss <cclauss@me.com>
190 lines
6.3 KiB
Python
190 lines
6.3 KiB
Python
"""
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Lorentz transformations describe the transition between two inertial reference
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frames F and F', each of which is moving in some direction with respect to the
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other. This code only calculates Lorentz transformations for movement in the x
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direction with no spatial rotation (i.e., a Lorentz boost in the x direction).
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The Lorentz transformations are calculated here as linear transformations of
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four-vectors [ct, x, y, z] described by Minkowski space. Note that t (time) is
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multiplied by c (the speed of light) in the first entry of each four-vector.
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Thus, if X = [ct; x; y; z] and X' = [ct'; x'; y'; z'] are the four-vectors for
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two inertial reference frames and X' moves in the x direction with velocity v
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with respect to X, then the Lorentz transformation from X to X' is X' = BX,
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where
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| y -γβ 0 0|
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B = |-γβ y 0 0|
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| 0 0 1 0|
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| 0 0 0 1|
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is the matrix describing the Lorentz boost between X and X',
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y = 1 / √(1 - v²/c²) is the Lorentz factor, and β = v/c is the velocity as
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a fraction of c.
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Reference: https://en.wikipedia.org/wiki/Lorentz_transformation
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"""
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from math import sqrt
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import numpy as np
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from sympy import symbols
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# Coefficient
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# Speed of light (m/s)
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c = 299792458
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# Symbols
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ct, x, y, z = symbols("ct x y z")
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# Vehicle's speed divided by speed of light (no units)
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def beta(velocity: float) -> float:
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"""
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Calculates β = v/c, the given velocity as a fraction of c
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>>> beta(c)
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1.0
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>>> beta(199792458)
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0.666435904801848
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>>> beta(1e5)
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0.00033356409519815205
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>>> beta(0.2)
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Traceback (most recent call last):
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...
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ValueError: Speed must be greater than or equal to 1!
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"""
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if velocity > c:
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raise ValueError("Speed must not exceed light speed 299,792,458 [m/s]!")
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elif velocity < 1:
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# Usually the speed should be much higher than 1 (c order of magnitude)
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raise ValueError("Speed must be greater than or equal to 1!")
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return velocity / c
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def gamma(velocity: float) -> float:
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"""
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Calculate the Lorentz factor y = 1 / √(1 - v²/c²) for a given velocity
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>>> gamma(4)
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1.0000000000000002
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>>> gamma(1e5)
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1.0000000556325075
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>>> gamma(3e7)
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1.005044845777813
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>>> gamma(2.8e8)
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2.7985595722318277
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>>> gamma(299792451)
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4627.49902669495
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>>> gamma(0.3)
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Traceback (most recent call last):
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...
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ValueError: Speed must be greater than or equal to 1!
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>>> gamma(2 * c)
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Traceback (most recent call last):
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...
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ValueError: Speed must not exceed light speed 299,792,458 [m/s]!
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"""
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return 1 / sqrt(1 - beta(velocity) ** 2)
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def transformation_matrix(velocity: float) -> np.ndarray:
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"""
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Calculate the Lorentz transformation matrix for movement in the x direction:
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| y -γβ 0 0|
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|-γβ y 0 0|
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| 0 0 1 0|
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| 0 0 0 1|
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where y is the Lorentz factor and β is the velocity as a fraction of c
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>>> transformation_matrix(29979245)
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array([[ 1.00503781, -0.10050378, 0. , 0. ],
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[-0.10050378, 1.00503781, 0. , 0. ],
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[ 0. , 0. , 1. , 0. ],
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[ 0. , 0. , 0. , 1. ]])
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>>> transformation_matrix(19979245.2)
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array([[ 1.00222811, -0.06679208, 0. , 0. ],
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[-0.06679208, 1.00222811, 0. , 0. ],
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[ 0. , 0. , 1. , 0. ],
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[ 0. , 0. , 0. , 1. ]])
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>>> transformation_matrix(1)
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array([[ 1.00000000e+00, -3.33564095e-09, 0.00000000e+00,
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0.00000000e+00],
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[-3.33564095e-09, 1.00000000e+00, 0.00000000e+00,
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0.00000000e+00],
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[ 0.00000000e+00, 0.00000000e+00, 1.00000000e+00,
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0.00000000e+00],
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[ 0.00000000e+00, 0.00000000e+00, 0.00000000e+00,
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1.00000000e+00]])
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>>> transformation_matrix(0)
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Traceback (most recent call last):
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...
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ValueError: Speed must be greater than or equal to 1!
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>>> transformation_matrix(c * 1.5)
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Traceback (most recent call last):
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...
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ValueError: Speed must not exceed light speed 299,792,458 [m/s]!
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"""
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return np.array(
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[
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[gamma(velocity), -gamma(velocity) * beta(velocity), 0, 0],
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[-gamma(velocity) * beta(velocity), gamma(velocity), 0, 0],
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[0, 0, 1, 0],
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[0, 0, 0, 1],
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]
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)
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def transform(velocity: float, event: np.ndarray | None = None) -> np.ndarray:
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"""
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Calculate a Lorentz transformation for movement in the x direction given a
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velocity and a four-vector for an inertial reference frame
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If no four-vector is given, then calculate the transformation symbolically
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with variables
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>>> transform(29979245, np.array([1, 2, 3, 4]))
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array([ 3.01302757e+08, -3.01302729e+07, 3.00000000e+00, 4.00000000e+00])
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>>> transform(29979245)
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array([1.00503781498831*ct - 0.100503778816875*x,
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-0.100503778816875*ct + 1.00503781498831*x, 1.0*y, 1.0*z],
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dtype=object)
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>>> transform(19879210.2)
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array([1.0022057787097*ct - 0.066456172618675*x,
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-0.066456172618675*ct + 1.0022057787097*x, 1.0*y, 1.0*z],
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dtype=object)
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>>> transform(299792459, np.array([1, 1, 1, 1]))
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Traceback (most recent call last):
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...
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ValueError: Speed must not exceed light speed 299,792,458 [m/s]!
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>>> transform(-1, np.array([1, 1, 1, 1]))
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Traceback (most recent call last):
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...
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ValueError: Speed must be greater than or equal to 1!
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"""
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# Ensure event is not empty
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if event is None:
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event = np.array([ct, x, y, z]) # Symbolic four vector
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else:
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event[0] *= c # x0 is ct (speed of light * time)
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return transformation_matrix(velocity) @ event
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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# Example of symbolic vector:
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four_vector = transform(29979245)
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print("Example of four vector: ")
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print(f"ct' = {four_vector[0]}")
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print(f"x' = {four_vector[1]}")
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print(f"y' = {four_vector[2]}")
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print(f"z' = {four_vector[3]}")
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# Substitute symbols with numerical values
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sub_dict = {ct: c, x: 1, y: 1, z: 1}
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numerical_vector = [four_vector[i].subs(sub_dict) for i in range(4)]
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print(f"\n{numerical_vector}")
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