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26 lines
461 B
Python
26 lines
461 B
Python
"""
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Self Powers
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Problem 48
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The series, 1^1 + 2^2 + 3^3 + ... + 10^10 = 10405071317.
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Find the last ten digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.
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"""
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def solution():
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"""
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Returns the last 10 digits of the series, 1^1 + 2^2 + 3^3 + ... + 1000^1000.
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>>> solution()
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'9110846700'
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"""
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total = 0
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for i in range(1, 1001):
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total += i**i
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return str(total)[-10:]
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if __name__ == "__main__":
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print(solution())
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