mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-12-18 17:20:16 +00:00
e3fa014a5a
* updating DIRECTORY.md
* Fix ruff
* Fix
* Fix
* Fix
* Revert "Fix"
This reverts commit 5bc3bf3422
.
* find_max.py: noqa: PLR1730
---------
Co-authored-by: MaximSmolskiy <MaximSmolskiy@users.noreply.github.com>
Co-authored-by: Christian Clauss <cclauss@me.com>
48 lines
1.1 KiB
Python
48 lines
1.1 KiB
Python
"""
|
|
Project Euler Problem 9: https://projecteuler.net/problem=9
|
|
|
|
Special Pythagorean triplet
|
|
|
|
A Pythagorean triplet is a set of three natural numbers, a < b < c, for which,
|
|
|
|
a^2 + b^2 = c^2
|
|
|
|
For example, 3^2 + 4^2 = 9 + 16 = 25 = 5^2.
|
|
|
|
There exists exactly one Pythagorean triplet for which a + b + c = 1000.
|
|
Find the product a*b*c.
|
|
|
|
References:
|
|
- https://en.wikipedia.org/wiki/Pythagorean_triple
|
|
"""
|
|
|
|
|
|
def solution(n: int = 1000) -> int:
|
|
"""
|
|
Return the product of a,b,c which are Pythagorean Triplet that satisfies
|
|
the following:
|
|
1. a < b < c
|
|
2. a**2 + b**2 = c**2
|
|
3. a + b + c = n
|
|
|
|
>>> solution(36)
|
|
1620
|
|
>>> solution(126)
|
|
66780
|
|
"""
|
|
|
|
product = -1
|
|
candidate = 0
|
|
for a in range(1, n // 3):
|
|
# Solving the two equations a**2+b**2=c**2 and a+b+c=N eliminating c
|
|
b = (n * n - 2 * a * n) // (2 * n - 2 * a)
|
|
c = n - a - b
|
|
if c * c == (a * a + b * b):
|
|
candidate = a * b * c
|
|
product = max(product, candidate)
|
|
return product
|
|
|
|
|
|
if __name__ == "__main__":
|
|
print(f"{solution() = }")
|