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* Added doctest and more explanation about Dijkstra execution. * tests were not passing with python2 due to missing __init__.py file at number_theory folder * Removed the dot at the beginning of the imported modules names because 'python3 -m doctest -v data_structures/hashing/*.py' and 'python3 -m doctest -v data_structures/stacks/*.py' were failing not finding hash_table.py and stack.py modules. * Moved global code to main scope and added doctest for project euler problems 1 to 14. * Added test case for negative input. * Changed N variable to do not use end of line scape because in case there is a space after it the script will break making it much more error prone. * Added problems description and doctests to the ones that were missing. Limited line length to 79 and executed python black over all scripts. * Changed the way files are loaded to support pytest call. * Added __init__.py to problems to make them modules and allow pytest execution. * Added project_euler folder to test units execution * Changed 'os.path.split(os.path.realpath(__file__))' to 'os.path.dirname()'
72 lines
1.4 KiB
Python
72 lines
1.4 KiB
Python
# -*- coding: utf-8 -*-
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"""
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Coin sums
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Problem 31
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In England the currency is made up of pound, £, and pence, p, and there are
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eight coins in general circulation:
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1p, 2p, 5p, 10p, 20p, 50p, £1 (100p) and £2 (200p).
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It is possible to make £2 in the following way:
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1×£1 + 1×50p + 2×20p + 1×5p + 1×2p + 3×1p
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How many different ways can £2 be made using any number of coins?
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"""
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from __future__ import print_function
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try:
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raw_input # Python 2
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except NameError:
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raw_input = input # Python 3
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def one_pence():
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return 1
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def two_pence(x):
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return 0 if x < 0 else two_pence(x - 2) + one_pence()
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def five_pence(x):
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return 0 if x < 0 else five_pence(x - 5) + two_pence(x)
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def ten_pence(x):
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return 0 if x < 0 else ten_pence(x - 10) + five_pence(x)
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def twenty_pence(x):
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return 0 if x < 0 else twenty_pence(x - 20) + ten_pence(x)
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def fifty_pence(x):
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return 0 if x < 0 else fifty_pence(x - 50) + twenty_pence(x)
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def one_pound(x):
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return 0 if x < 0 else one_pound(x - 100) + fifty_pence(x)
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def two_pound(x):
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return 0 if x < 0 else two_pound(x - 200) + one_pound(x)
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def solution(n):
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"""Returns the number of different ways can £n be made using any number of
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coins?
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>>> solution(500)
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6295434
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>>> solution(200)
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73682
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>>> solution(50)
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451
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>>> solution(10)
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11
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"""
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return two_pound(n)
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if __name__ == "__main__":
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print(solution(int(str(input()).strip())))
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