mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-11-24 13:31:07 +00:00
51 lines
900 B
Python
51 lines
900 B
Python
from __future__ import print_function
|
|
|
|
'''
|
|
Problem Statement:
|
|
If we list all the natural numbers below 10 that are multiples of 3 or 5,
|
|
we get 3,5,6 and 9. The sum of these multiples is 23.
|
|
Find the sum of all the multiples of 3 or 5 below N.
|
|
'''
|
|
'''
|
|
This solution is based on the pattern that the successive numbers in the series follow: 0+3,+2,+1,+3,+1,+2,+3.
|
|
'''
|
|
|
|
try:
|
|
raw_input # Python 2
|
|
except NameError:
|
|
raw_input = input # Python 3
|
|
n = int(raw_input().strip())
|
|
sum=0
|
|
num=0
|
|
while(1):
|
|
num+=3
|
|
if(num>=n):
|
|
break
|
|
sum+=num
|
|
num+=2
|
|
if(num>=n):
|
|
break
|
|
sum+=num
|
|
num+=1
|
|
if(num>=n):
|
|
break
|
|
sum+=num
|
|
num+=3
|
|
if(num>=n):
|
|
break
|
|
sum+=num
|
|
num+=1
|
|
if(num>=n):
|
|
break
|
|
sum+=num
|
|
num+=2
|
|
if(num>=n):
|
|
break
|
|
sum+=num
|
|
num+=3
|
|
if(num>=n):
|
|
break
|
|
sum+=num
|
|
|
|
print(sum);
|