mirror of
https://github.com/TheAlgorithms/Python.git
synced 2024-12-05 02:40:16 +00:00
64543faa98
* Make some ruff fixes * Undo manual fix * Undo manual fix * Updates from ruff=0.0.251
80 lines
1.7 KiB
Python
80 lines
1.7 KiB
Python
"""
|
|
Project Euler Problem 9: https://projecteuler.net/problem=9
|
|
|
|
Special Pythagorean triplet
|
|
|
|
A Pythagorean triplet is a set of three natural numbers, a < b < c, for which,
|
|
|
|
a^2 + b^2 = c^2
|
|
|
|
For example, 3^2 + 4^2 = 9 + 16 = 25 = 5^2.
|
|
|
|
There exists exactly one Pythagorean triplet for which a + b + c = 1000.
|
|
Find the product a*b*c.
|
|
|
|
References:
|
|
- https://en.wikipedia.org/wiki/Pythagorean_triple
|
|
"""
|
|
|
|
|
|
def solution() -> int:
|
|
"""
|
|
Returns the product of a,b,c which are Pythagorean Triplet that satisfies
|
|
the following:
|
|
1. a < b < c
|
|
2. a**2 + b**2 = c**2
|
|
3. a + b + c = 1000
|
|
|
|
>>> solution()
|
|
31875000
|
|
"""
|
|
|
|
for a in range(300):
|
|
for b in range(a + 1, 400):
|
|
for c in range(b + 1, 500):
|
|
if (a + b + c) == 1000 and (a**2) + (b**2) == (c**2):
|
|
return a * b * c
|
|
|
|
return -1
|
|
|
|
|
|
def solution_fast() -> int:
|
|
"""
|
|
Returns the product of a,b,c which are Pythagorean Triplet that satisfies
|
|
the following:
|
|
1. a < b < c
|
|
2. a**2 + b**2 = c**2
|
|
3. a + b + c = 1000
|
|
|
|
>>> solution_fast()
|
|
31875000
|
|
"""
|
|
|
|
for a in range(300):
|
|
for b in range(400):
|
|
c = 1000 - a - b
|
|
if a < b < c and (a**2) + (b**2) == (c**2):
|
|
return a * b * c
|
|
|
|
return -1
|
|
|
|
|
|
def benchmark() -> None:
|
|
"""
|
|
Benchmark code comparing two different version function.
|
|
"""
|
|
import timeit
|
|
|
|
print(
|
|
timeit.timeit("solution()", setup="from __main__ import solution", number=1000)
|
|
)
|
|
print(
|
|
timeit.timeit(
|
|
"solution_fast()", setup="from __main__ import solution_fast", number=1000
|
|
)
|
|
)
|
|
|
|
|
|
if __name__ == "__main__":
|
|
print(f"{solution() = }")
|