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a5000d32ed
* Fix typehints in project_euler/problem01
Squashed commit of the following:
commit 6801d073b31bf702814861cd3b07b634ca295bfa
Author: Archaengel <god11341258@gmail.com>
Date: Mon Oct 5 16:40:10 2020 -0700
Fix typehints in project_euler/problem01
commit 29afc3af114abd1b99dc3f7c8fc99128229db131
Author: Archaengel <god11341258@gmail.com>
Date: Mon Oct 5 15:06:34 2020 -0700
Add typehints and default argument for project_euler/problem_01
* Add default args, typehints, and expand variable names for PE prob 02
* Add style improvements for first solution of PE Problem 02
* Add default arg and typehints for second solution of PE Problem 02
* Add default arg for third solution of PE Problem 02
* Add style improvements for 1st soln of PE problem 03
* Add default arg and typehints for 2nd soln of PE problem 03
* Add default arg for 3rd soln of PE problem 03
* Remove unnecessary newlines
* Remove unnecessary newlines
* Fix end of file for 2nd soln in PE problem 03
* Add style improvements to solutions for PE problem 04
* Restore original newlines in soln for PE problem 04
* Fix punctuation in docstring for PE problem 04
* Restore solution bodies for PE problem 04
* Expand variable names for 2nd soln of PE problem 04
52 lines
1.4 KiB
Python
52 lines
1.4 KiB
Python
"""
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Problem:
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A palindromic number reads the same both ways. The largest palindrome made from
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the product of two 2-digit numbers is 9009 = 91 x 99.
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Find the largest palindrome made from the product of two 3-digit numbers which
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is less than N.
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"""
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def solution(n: int = 998001) -> int:
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"""Returns the largest palindrome made from the product of two 3-digit
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numbers which is less than n.
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>>> solution(20000)
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19591
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>>> solution(30000)
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29992
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>>> solution(40000)
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39893
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>>> solution(10000)
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Traceback (most recent call last):
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...
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ValueError: That number is larger than our acceptable range.
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"""
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# fetches the next number
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for number in range(n - 1, 9999, -1):
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# converts number into string.
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str_number = str(number)
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# checks whether 'str_number' is a palindrome.
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if str_number == str_number[::-1]:
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divisor = 999
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# if 'number' is a product of two 3-digit numbers
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# then number is the answer otherwise fetch next number.
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while divisor != 99:
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if (number % divisor == 0) and (len(str(number // divisor)) == 3.0):
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return number
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divisor -= 1
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raise ValueError("That number is larger than our acceptable range.")
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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print(solution(int(input().strip())))
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