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The function count_zeros_and_ones takes a binary number as input. It converts the number to a string and counts the occurrences of 0 and 1 using the count() method. It returns the counts, which are then printed out. You can replace binary_number with any binary number you'd like to analyze!
62 lines
1.7 KiB
Python
62 lines
1.7 KiB
Python
from math import log2
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def binary_count_trailing_zeros(a: int) -> int:
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"""
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Take in 1 integer, return a number that is
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the number of trailing zeros in binary representation of that number.
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>>> binary_count_trailing_zeros(25)
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0
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>>> binary_count_trailing_zeros(36)
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2
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>>> binary_count_trailing_zeros(16)
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4
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>>> binary_count_trailing_zeros(58)
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1
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>>> binary_count_trailing_zeros(4294967296)
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32
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>>> binary_count_trailing_zeros(0)
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0
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>>> binary_count_trailing_zeros(-10)
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Traceback (most recent call last):
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...
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ValueError: Input value must be a positive integer
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>>> binary_count_trailing_zeros(0.8)
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Traceback (most recent call last):
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...
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TypeError: Input value must be a 'int' type
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>>> binary_count_trailing_zeros("0")
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Traceback (most recent call last):
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...
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TypeError: '<' not supported between instances of 'str' and 'int'
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"""
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if a < 0:
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raise ValueError("Input value must be a positive integer")
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elif isinstance(a, float):
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raise TypeError("Input value must be a 'int' type")
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return 0 if (a == 0) else int(log2(a & -a))
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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# counting number of 0s and 1s in a binary number
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def count_zeros_and_ones(binary_number):
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# Convert the binary number to a string if it's not already
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binary_str = str(binary_number)
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count_zeros = binary_str.count('0')
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count_ones = binary_str.count('1')
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return count_zeros, count_ones
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# Example usage
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binary_number = 1011001
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zeros, ones = count_zeros_and_ones(binary_number)
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print(f"Number of 0s: {zeros}, Number of 1s: {ones}")
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