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90 lines
3.5 KiB
Python
90 lines
3.5 KiB
Python
def bailey_borwein_plouffe(digit_position: int, precision: int = 1000) -> str:
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"""
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Implement a popular pi-digit-extraction algorithm known as the
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Bailey-Borwein-Plouffe (BBP) formula to calculate the nth hex digit of pi.
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Wikipedia page:
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https://en.wikipedia.org/wiki/Bailey%E2%80%93Borwein%E2%80%93Plouffe_formula
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@param digit_position: a positive integer representing the position of the digit to
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extract.
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The digit immediately after the decimal point is located at position 1.
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@param precision: number of terms in the second summation to calculate.
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A higher number reduces the chance of an error but increases the runtime.
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@return: a hexadecimal digit representing the digit at the nth position
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in pi's decimal expansion.
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>>> "".join(bailey_borwein_plouffe(i) for i in range(1, 11))
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'243f6a8885'
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>>> bailey_borwein_plouffe(5, 10000)
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'6'
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>>> bailey_borwein_plouffe(-10)
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Traceback (most recent call last):
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...
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ValueError: Digit position must be a positive integer
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>>> bailey_borwein_plouffe(0)
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Traceback (most recent call last):
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...
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ValueError: Digit position must be a positive integer
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>>> bailey_borwein_plouffe(1.7)
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Traceback (most recent call last):
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...
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ValueError: Digit position must be a positive integer
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>>> bailey_borwein_plouffe(2, -10)
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Traceback (most recent call last):
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...
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ValueError: Precision must be a nonnegative integer
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>>> bailey_borwein_plouffe(2, 1.6)
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Traceback (most recent call last):
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...
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ValueError: Precision must be a nonnegative integer
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"""
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if (not isinstance(digit_position, int)) or (digit_position <= 0):
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raise ValueError("Digit position must be a positive integer")
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elif (not isinstance(precision, int)) or (precision < 0):
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raise ValueError("Precision must be a nonnegative integer")
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# compute an approximation of (16 ** (n - 1)) * pi whose fractional part is mostly
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# accurate
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sum_result = (
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4 * _subsum(digit_position, 1, precision)
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- 2 * _subsum(digit_position, 4, precision)
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- _subsum(digit_position, 5, precision)
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- _subsum(digit_position, 6, precision)
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)
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# return the first hex digit of the fractional part of the result
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return hex(int((sum_result % 1) * 16))[2:]
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def _subsum(
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digit_pos_to_extract: int, denominator_addend: int, precision: int
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) -> float:
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# only care about first digit of fractional part; don't need decimal
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"""
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Private helper function to implement the summation
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functionality.
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@param digit_pos_to_extract: digit position to extract
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@param denominator_addend: added to denominator of fractions in the formula
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@param precision: same as precision in main function
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@return: floating-point number whose integer part is not important
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"""
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sum = 0.0
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for sum_index in range(digit_pos_to_extract + precision):
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denominator = 8 * sum_index + denominator_addend
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if sum_index < digit_pos_to_extract:
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# if the exponential term is an integer and we mod it by the denominator
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# before dividing, only the integer part of the sum will change;
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# the fractional part will not
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exponential_term = pow(
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16, digit_pos_to_extract - 1 - sum_index, denominator
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)
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else:
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exponential_term = pow(16, digit_pos_to_extract - 1 - sum_index)
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sum += exponential_term / denominator
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return sum
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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