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52cf668617
* Add sol3 for project_euler proble_03 * Update sol3.py add type hint remove unused variable * Format code with psf/black * add sol3 to project_euler/problem_08, modify the stepsize of the loop,will be faster than sol1
84 lines
3.0 KiB
Python
84 lines
3.0 KiB
Python
# -*- coding: utf-8 -*-
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"""
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The four adjacent digits in the 1000-digit number that have the greatest
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product are 9 × 9 × 8 × 9 = 5832.
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73167176531330624919225119674426574742355349194934
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96983520312774506326239578318016984801869478851843
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85861560789112949495459501737958331952853208805511
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12540698747158523863050715693290963295227443043557
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66896648950445244523161731856403098711121722383113
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62229893423380308135336276614282806444486645238749
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30358907296290491560440772390713810515859307960866
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70172427121883998797908792274921901699720888093776
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65727333001053367881220235421809751254540594752243
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52584907711670556013604839586446706324415722155397
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53697817977846174064955149290862569321978468622482
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83972241375657056057490261407972968652414535100474
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82166370484403199890008895243450658541227588666881
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16427171479924442928230863465674813919123162824586
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17866458359124566529476545682848912883142607690042
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24219022671055626321111109370544217506941658960408
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07198403850962455444362981230987879927244284909188
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84580156166097919133875499200524063689912560717606
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05886116467109405077541002256983155200055935729725
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71636269561882670428252483600823257530420752963450
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Find the thirteen adjacent digits in the 1000-digit number that have the
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greatest product. What is the value of this product?
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"""
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import sys
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N = """73167176531330624919225119674426574742355349194934\
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96983520312774506326239578318016984801869478851843\
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85861560789112949495459501737958331952853208805511\
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12540698747158523863050715693290963295227443043557\
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66896648950445244523161731856403098711121722383113\
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62229893423380308135336276614282806444486645238749\
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30358907296290491560440772390713810515859307960866\
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70172427121883998797908792274921901699720888093776\
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65727333001053367881220235421809751254540594752243\
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52584907711670556013604839586446706324415722155397\
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53697817977846174064955149290862569321978468622482\
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83972241375657056057490261407972968652414535100474\
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82166370484403199890008895243450658541227588666881\
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16427171479924442928230863465674813919123162824586\
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17866458359124566529476545682848912883142607690042\
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24219022671055626321111109370544217506941658960408\
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07198403850962455444362981230987879927244284909188\
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84580156166097919133875499200524063689912560717606\
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05886116467109405077541002256983155200055935729725\
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71636269561882670428252483600823257530420752963450"""
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def streval(s: str) -> int:
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ret = 1
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for it in s:
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ret *= int(it)
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return ret
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def solution(n: str) -> int:
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"""Find the thirteen adjacent digits in the 1000-digit number n that have
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the greatest product and returns it.
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>>> solution(N)
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23514624000
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"""
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LargestProduct = -sys.maxsize - 1
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substr = n[:13]
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cur_index = 13
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while cur_index < len(n) - 13:
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if int(n[cur_index]) >= int(substr[0]):
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substr = substr[1:] + n[cur_index]
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cur_index += 1
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else:
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LargestProduct = max(LargestProduct, streval(substr))
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substr = n[cur_index : cur_index + 13]
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cur_index += 13
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return LargestProduct
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if __name__ == "__main__":
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print(solution(N))
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