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42 lines
768 B
Python
42 lines
768 B
Python
'''
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Problem Statement:
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If we list all the natural numbers below 10 that are multiples of 3 or 5,
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we get 3,5,6 and 9. The sum of these multiples is 23.
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Find the sum of all the multiples of 3 or 5 below N.
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'''
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'''
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This solution is based on the pattern that the successive numbers in the series follow: 0+3,+2,+1,+3,+1,+2,+3.
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'''
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n = int(raw_input().strip())
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sum=0;
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num=0;
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while(1):
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num+=3
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if(num>=n):
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break
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sum+=num
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num+=2
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if(num>=n):
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break
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sum+=num
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num+=1
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if(num>=n):
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break
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sum+=num
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num+=3
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if(num>=n):
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break
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sum+=num
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num+=1
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if(num>=n):
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break
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sum+=num
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num+=2
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if(num>=n):
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break
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sum+=num
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num+=3
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if(num>=n):
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break
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sum+=num
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print sum; |