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43 lines
1.1 KiB
Python
43 lines
1.1 KiB
Python
"""
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Euler Problem 26
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https://projecteuler.net/problem=26
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Find the value of d < 1000 for which 1/d contains the longest recurring cycle
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in its decimal fraction part.
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"""
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def find_digit(numerator: int, digit: int) -> int:
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"""
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Considering any range can be provided,
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because as per the problem, the digit d < 1000
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>>> find_digit(1, 10)
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7
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>>> find_digit(10, 100)
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97
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>>> find_digit(10, 1000)
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983
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"""
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the_digit = 1
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longest_list_length = 0
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for divide_by_number in range(numerator, digit + 1):
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has_been_divided = []
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now_divide = numerator
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for division_cycle in range(1, digit + 1):
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if now_divide in has_been_divided:
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if longest_list_length < len(has_been_divided):
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longest_list_length = len(has_been_divided)
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the_digit = divide_by_number
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else:
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has_been_divided.append(now_divide)
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now_divide = now_divide * 10 % divide_by_number
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return the_digit
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# Tests
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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