Python/dynamic_programming/minimum_partition.py
Caeden 07e991d553
Add pep8-naming to pre-commit hooks and fixes incorrect naming conventions (#7062)
* ci(pre-commit): Add pep8-naming to `pre-commit` hooks (#7038)

* refactor: Fix naming conventions (#7038)

* Update arithmetic_analysis/lu_decomposition.py

Co-authored-by: Christian Clauss <cclauss@me.com>

* [pre-commit.ci] auto fixes from pre-commit.com hooks

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* refactor(lu_decomposition): Replace `NDArray` with `ArrayLike` (#7038)

* chore: Fix naming conventions in doctests (#7038)

* fix: Temporarily disable project euler problem 104 (#7069)

* chore: Fix naming conventions in doctests (#7038)

Co-authored-by: Christian Clauss <cclauss@me.com>
Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com>
2022-10-13 00:54:20 +02:00

31 lines
655 B
Python

"""
Partition a set into two subsets such that the difference of subset sums is minimum
"""
def find_min(arr):
n = len(arr)
s = sum(arr)
dp = [[False for x in range(s + 1)] for y in range(n + 1)]
for i in range(1, n + 1):
dp[i][0] = True
for i in range(1, s + 1):
dp[0][i] = False
for i in range(1, n + 1):
for j in range(1, s + 1):
dp[i][j] = dp[i][j - 1]
if arr[i - 1] <= j:
dp[i][j] = dp[i][j] or dp[i - 1][j - arr[i - 1]]
for j in range(int(s / 2), -1, -1):
if dp[n][j] is True:
diff = s - 2 * j
break
return diff