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0601b56173
* Contributes to #9943 Added doctest to largest_of_very_large_numbers.py Added doctest to word_patterns.py Added doctest to onepad_cipher.py * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Contributes to #9943 Added doctest to maths/largest_of_very_large_numbers.py Added doctest to strings/word_patterns.py Added doctest to ciphers/onepad_cipher.py * Add tests without modifying code #10740 Added test to maths/largest_of_very_large_numbers Added test to strings/word_patterns.py Added test to ciphers/onepad_cipher.py --------- Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com>
50 lines
1.3 KiB
Python
50 lines
1.3 KiB
Python
# Author: Abhijeeth S
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import math
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def res(x, y):
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"""
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Reduces large number to a more manageable number
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>>> res(5, 7)
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4.892790030352132
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>>> res(0, 5)
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0
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>>> res(3, 0)
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1
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>>> res(-1, 5)
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Traceback (most recent call last):
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...
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ValueError: math domain error
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"""
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if 0 not in (x, y):
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# We use the relation x^y = y*log10(x), where 10 is the base.
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return y * math.log10(x)
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else:
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if x == 0: # 0 raised to any number is 0
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return 0
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elif y == 0:
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return 1 # any number raised to 0 is 1
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raise AssertionError("This should never happen")
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if __name__ == "__main__": # Main function
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# Read two numbers from input and typecast them to int using map function.
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# Here x is the base and y is the power.
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prompt = "Enter the base and the power separated by a comma: "
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x1, y1 = map(int, input(prompt).split(","))
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x2, y2 = map(int, input(prompt).split(","))
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# We find the log of each number, using the function res(), which takes two
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# arguments.
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res1 = res(x1, y1)
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res2 = res(x2, y2)
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# We check for the largest number
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if res1 > res2:
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print("Largest number is", x1, "^", y1)
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elif res2 > res1:
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print("Largest number is", x2, "^", y2)
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else:
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print("Both are equal")
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