Python/backtracking/n_queens.py
Hetal Kuvadia 831558d38d #945 Backtracking Algorithms (#953)
* Adding nqueens.py for backtracking

* Adding sum_of_subsets.py for backtracking

* Update nqueens.py

* Rename nqueens.py to n_queens.py

* Deleting /other/n_queens.py
2019-07-05 14:18:36 +05:30

85 lines
2.4 KiB
Python

'''
The nqueens problem is of placing N queens on a N * N
chess board such that no queen can attack any other queens placed
on that chess board.
This means that one queen cannot have any other queen on its horizontal, vertical and
diagonal lines.
'''
solution = []
def isSafe(board, row, column):
'''
This function returns a boolean value True if it is safe to place a queen there considering
the current state of the board.
Parameters :
board(2D matrix) : board
row ,column : coordinates of the cell on a board
Returns :
Boolean Value
'''
for i in range(len(board)):
if board[row][i] == 1:
return False
for i in range(len(board)):
if board[i][column] == 1:
return False
for i,j in zip(range(row,-1,-1),range(column,-1,-1)):
if board[i][j] == 1:
return False
for i,j in zip(range(row,-1,-1),range(column,len(board))):
if board[i][j] == 1:
return False
return True
def solve(board, row):
'''
It creates a state space tree and calls the safe function untill it receives a
False Boolean and terminates that brach and backtracks to the next
poosible solution branch.
'''
if row >= len(board):
'''
If the row number exceeds N we have board with a successful combination
and that combination is appended to the solution list and the board is printed.
'''
solution.append(board)
printboard(board)
print()
return
for i in range(len(board)):
'''
For every row it iterates through each column to check if it is feesible to place a
queen there.
If all the combinations for that particaular branch are successfull the board is
reinitialized for the next possible combination.
'''
if isSafe(board,row,i):
board[row][i] = 1
solve(board,row+1)
board[row][i] = 0
return False
def printboard(board):
'''
Prints the boards that have a successfull combination.
'''
for i in range(len(board)):
for j in range(len(board)):
if board[i][j] == 1:
print("Q", end = " ")
else :
print(".", end = " ")
print()
#n=int(input("The no. of queens"))
n = 8
board = [[0 for i in range(n)]for j in range(n)]
solve(board, 0)
print("The total no. of solutions are :", len(solution))