267b5eff40
* Added doctest and more explanation about Dijkstra execution. * tests were not passing with python2 due to missing __init__.py file at number_theory folder * Removed the dot at the beginning of the imported modules names because 'python3 -m doctest -v data_structures/hashing/*.py' and 'python3 -m doctest -v data_structures/stacks/*.py' were failing not finding hash_table.py and stack.py modules. * Moved global code to main scope and added doctest for project euler problems 1 to 14. * Added test case for negative input. * Changed N variable to do not use end of line scape because in case there is a space after it the script will break making it much more error prone. * Added problems description and doctests to the ones that were missing. Limited line length to 79 and executed python black over all scripts. * Changed the way files are loaded to support pytest call. * Added __init__.py to problems to make them modules and allow pytest execution. * Added project_euler folder to test units execution * Changed 'os.path.split(os.path.realpath(__file__))' to 'os.path.dirname()' |
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| .. | ||
| problem_01 | ||
| problem_02 | ||
| problem_03 | ||
| problem_04 | ||
| problem_05 | ||
| problem_06 | ||
| problem_07 | ||
| problem_08 | ||
| problem_09 | ||
| problem_10 | ||
| problem_11 | ||
| problem_12 | ||
| problem_13 | ||
| problem_14 | ||
| problem_15 | ||
| problem_16 | ||
| problem_17 | ||
| problem_19 | ||
| problem_20 | ||
| problem_21 | ||
| problem_22 | ||
| problem_24 | ||
| problem_25 | ||
| problem_28 | ||
| problem_29 | ||
| problem_31 | ||
| problem_36 | ||
| problem_40 | ||
| problem_48 | ||
| problem_52 | ||
| problem_53 | ||
| problem_76 | ||
| problem_234 | ||
| README.md | ||
ProjectEuler
Problems are taken from https://projecteuler.net/.
Project Euler is a series of challenging mathematical/computer programming problems that will require more than just mathematical insights to solve. Project Euler is ideal for mathematicians who are learning to code.
Here the efficiency of your code is also checked. I've tried to provide all the best possible solutions.
PROBLEMS:
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If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3,5,6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below N.
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Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1,2,3,5,8,13,21,34,55,89,.. By considering the terms in the Fibonacci sequence whose values do not exceed n, find the sum of the even-valued terms.
e.g. for n=10, we have {2,8}, sum is 10. -
The prime factors of 13195 are 5,7,13 and 29. What is the largest prime factor of a given number N? e.g. for 10, largest prime factor = 5. For 17, largest prime factor = 17.
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A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99. Find the largest palindrome made from the product of two 3-digit numbers which is less than N.
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2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible(divisible with no remainder) by all of the numbers from 1 to N?
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The sum of the squares of the first ten natural numbers is, 1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)^2 = 552 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640. Find the difference between the sum of the squares of the first N natural numbers and the square of the sum.
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By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13. What is the Nth prime number?
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A Pythagorean triplet is a set of three natural numbers, a < b < c, for which, a^2 + b^2 = c^2 There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc.
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The following iterative sequence is defined for the set of positive integers: n → n/2 (n is even) n → 3n + 1 (n is odd) Using the rule above and starting with 13, we generate the following sequence: 13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1 Which starting number, under one million, produces the longest chain?
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2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26. What is the sum of the digits of the number 2^1000?
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n! means n × (n − 1) × ... × 3 × 2 × 1 For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800, and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27. Find the sum of the digits in the number 100!