Python/project_euler/problem_078/sol1.py
Prakhar Gurunani 329feb4928
Add Project Euler Problem 078 solution 01 (#5565)
* Create sol1.py

* updating DIRECTORY.md

* Create __init__.py

* Add docstring

* Reformat with black

* Fix flake8 issues

* Add EOL

* Fix formatting issues

* Add docstring

* Add func return type

* Change return type

* Remove test print statement

* Reformat code

* Fix return types

* Break loop

* Update doctest sol

* Update project_euler/problem_078/sol1.py

Co-authored-by: John Law <johnlaw.po@gmail.com>

* Added doctest and changed return type

* Add int()

* Fix flake8 issues

* Use argument instead of fixed constant

* Update sol1.py

* fix sol1.py

Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
Co-authored-by: John Law <johnlaw.po@gmail.com>
2021-10-27 17:19:04 +08:00

56 lines
1.2 KiB
Python

"""
Problem 78
Url: https://projecteuler.net/problem=78
Statement:
Let p(n) represent the number of different ways in which n coins
can be separated into piles. For example, five coins can be separated
into piles in exactly seven different ways, so p(5)=7.
OOOOO
OOOO O
OOO OO
OOO O O
OO OO O
OO O O O
O O O O O
Find the least value of n for which p(n) is divisible by one million.
"""
import itertools
def solution(number: int = 1000000) -> int:
"""
>>> solution()
55374
"""
partitions = [1]
for i in itertools.count(len(partitions)):
item = 0
for j in itertools.count(1):
sign = -1 if j % 2 == 0 else +1
index = (j * j * 3 - j) // 2
if index > i:
break
item += partitions[i - index] * sign
index += j
if index > i:
break
item += partitions[i - index] * sign
item %= number
if item == 0:
return i
partitions.append(item)
return 0
if __name__ == "__main__":
import doctest
doctest.testmod()
print(f"{solution() = }")