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9fcfe6a02b
* Added doctest and more explanation about Dijkstra execution. * tests were not passing with python2 due to missing __init__.py file at number_theory folder * Removed the dot at the beginning of the imported modules names because 'python3 -m doctest -v data_structures/hashing/*.py' and 'python3 -m doctest -v data_structures/stacks/*.py' were failing not finding hash_table.py and stack.py modules. * Moved global code to main scope and added doctest for project euler problems 1 to 14. * Added test case for negative input. * Changed N variable to do not use end of line scape because in case there is a space after it the script will break making it much more error prone. * Added problems description and doctests to the ones that were missing. Limited line length to 79 and executed python black over all scripts. * Changed the way files are loaded to support pytest call. * Added __init__.py to problems to make them modules and allow pytest execution. * Added project_euler folder to test units execution * Changed 'os.path.split(os.path.realpath(__file__))' to 'os.path.dirname()' * Added Burrows-Wheeler transform algorithm. * Added changes suggested by cclauss * Fixes for issue 'Fix the LGTM issues #1024'. * Added doctest for different parameter types and negative values. * Fixed doctest issue added at last commit. * Commented doctest that were causing slowness at Travis. * Added comment with the reason for some doctest commented. * pytest --ignore * Added tests execution again. * Had forgotten to add comment to file project_euler/problem_09/sol3.py
39 lines
854 B
Python
39 lines
854 B
Python
"""
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Problem Statement:
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A Pythagorean triplet is a set of three natural numbers, a < b < c, for which,
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a^2 + b^2 = c^2
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For example, 3^2 + 4^2 = 9 + 16 = 25 = 5^2.
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There exists exactly one Pythagorean triplet for which a + b + c = 1000.
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Find the product abc.
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"""
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from __future__ import print_function
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def solution():
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"""
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Returns the product of a,b,c which are Pythagorean Triplet that satisfies
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the following:
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1. a**2 + b**2 = c**2
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2. a + b + c = 1000
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# The code below has been commented due to slow execution affecting Travis.
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# >>> solution()
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# 31875000
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"""
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return [
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a * b * c
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for a in range(1, 999)
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for b in range(a, 999)
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for c in range(b, 999)
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if (a * a + b * b == c * c) and (a + b + c == 1000)
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][0]
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if __name__ == "__main__":
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print(solution())
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